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Re: Another formula to throw on the fire
From: D.C. Cox[SMTP:DR.RESONANCE-at-next-wave-dot-net]
Sent: Thursday, December 11, 1997 6:57 PM
To: Tesla List
Subject: Re: Another formula to throw on the fire
to: Adam
Great idea! It's an equation I have never seen in print before. One
question: Is the radius measured from the center of the circle?? Not sure
what you mean by center of the tubing?
DR.RESONANCE-at-next-wave-dot-net
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> From: Tesla List <tesla-at-pupman-dot-com>
> To: 'Tesla List' <tesla-at-poodle.pupman-dot-com>
> Subject: Another formula to throw on the fire
> Date: Thursday, December 11, 1997 8:13 AM
>
>
> From: Adam[SMTP:absmith-at-tiac-dot-net]
> Sent: Wednesday, December 10, 1997 9:57 PM
> To: tesla list
> Subject: Another formula to throw on the fire
>
>
> I computed a simple integration for finding out how much tubing or wire
> is need for a primary coil that may be of use to those building coils.
> The formula is as follows:
>
> For a flat (or slightly banked) spiral primary coil of:
>
> Inside (starting) radius Ri
> Outside (final) radius of Ro (Both Radii measured from the center of
> the tubing)
> N number of turns
>
> The total length of wire/tubing (L) required is: pi * N * (Ro + Ri)
> Pretty simple end result, eh? Independent of units chosen too, as long
> as you are consistant of course!
>
>
> ---------------------------
> For completeness, here is my entire calculation:
>
> The integrand was radius as a function of Theta:
>
> R = (W/2pi) * (Ro - Ri)/N + Ri where W is Theta in Radians
>
> Integrating the radius this over all 2*pi*N turns (henceforth 2piN) we
> get L:
>
> _ (2piN)
> /
> L = / [(W/2pi)(Ro - Ri)/N + Ri] dW
> _/
> 0
>
>
> L = [(Ro - Ri)/2piN] * [(2piN)^2/2] + 2piN*Ri
>
>
> L = piN(Ro-Ri) + 2piN*Ri
>
>
> L = piN(Ro-Ri) [Q.E.D.]
>
> -Adam
>
>
>
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> absmith-at-tiac-dot-net
> Epoch, Inc. Digital Music Project
>
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