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1/4 WAVE SECONDARIES

To: teslaatgrendel.objincdotcom

Subject: 1/4 WAVE SECONDARIES

From: "Malcolm Watts" <MALCOLMatdirectorate.wnp.ac.nz>

Date: Thu, 19 Oct 1995 08:38:41 +1200

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SECONDARY ANALYSIS 2
********************
This part of the exercise examines the effects of different windings
for a given coil former. Three different formers are considered, each
having the same diameter but a different height (and hence h/d ratio).
The investigation revealed some remarkable facts about the effect of
forcing each coil to resonate at a frequency such that the wire in each
coil is 1/4 wavelength long at that frequency.
The diameter of all coils is 12". The h/d ratios considered are 2,3
and 4. For a given h/d ratio and diameter, the selfcapacitance of the
coils are predetermined prior to adding a terminal. Changing the wire
diameter for a given former size changes the number of turns, inductance
and therefore resonant frequency of each coil in addition to wirelength.
The selfcapacitance does not change under these conditions.
The procedure for generating the coils is as follows :
(1) Choose h/d ratio and Dsec, hence Hsec and selfcapacitance follow
(2) Choose a wire gauge
(3) From the table Richard Q. supplied, the number of turns for the
chosen wire gauge is defined (this table takes wire insulation
thickness into account)
(4) Calculate the coil inductance
(5) Calculate the length of wire used
(6) Calculate the 1/4 wavelength frequency based on wirelength
(7) Calculate the total capacitance (Ctot = Csec+Cterm) required to
make the coil resonate at this frequency
(8) Calculate the thickness of wire in terms of skin depths for this
frequency (this determines the suitability of the chosen wire gauge
at this frequency)
(9) Calculate Lsec/Ctot ratio (mH/pF)
NOTE : Q is considered incalculable due to factors such as radiation
resistance (i.e. I haven't figured out how to do it yet).
TABLE 1 : h/d ratio = 2, Hsec = 24", Csec = 15.2pF
Dwire(mm)  Nsec  Lsec(mH)  Lwire(in)  f(kHz)  Ctot(pF)  Skin  L/C

0.8  696  59.5  26239  112.5  33.6  4.1  1.77
1.0  552  37.4  20810  141.9  33.6  5.7  1.11
1.2  480  28.3  18096  163.2  33.6  7.3  0.84
TABLE 2 : h/d ratio = 3, Hsec = 36", Csec = 18.6pF
Dwire(mm)  Nsec  Lsec(mH)  Lwire(in)  f(kHz)  Ctot(pF)  Skin  L/C

0.8  1044  95.0  39358  75.0  47.4  3.3  2.00
1.0  828  60.0  31215  94.6  47.4  4.7  1.27
1.2  720  45.2  27143  108.8  47.4  6.0  0.95
TABLE 3 : h/d ratio = 4, Hsec = 48", Csec = 22pF
Dwire(mm)  Nsec  Lsec(mH)  Lwire(in)  f(kHz)  Ctot(pF)  Skin  L/C

0.8  1392  130.9  52477  56.3  61.0  2.85  2.15
1.0  1104  82.3  41620  71.0  61.0  4.3  1.35
1.2  960  62.3  36191  81.6  61.0  5.2  1.02
NOTES :
 For a chosen h/d ratio, the capacitance required to force ANY
coil to resonate so as to make the wire 1/4 wavelength long is
identical!! Since selfcapacitance is constant for any coil with
the same diameter and h/d ratio, the terminal capacitance is
always the same as well! It would appear that this constancy has
been the basis for the many attempts to base 1/4 wave length on
h/d ratio.
 Based on the above finding, the total capacitance required for
a coil to be 1/4 wavelength long for a particular former may
be found by designing ANY coil for that former and going through
the calculation steps as shown above to find the required cap
acitance value.
 There is a clear tradeoff between skin resistance and L/C ratio
for the coils in each group since an increase in wire size implies
greater current carrying area as well as reduced inductance due
to fewer turns.
 For some sacrifice in skin performance, the first coil in TABLE3
has a much higher inductance than the first coil in TABLE2. The
L/C ratio is also higher but not by much (Q is proportional to
the square root of L/C and inversely proportional to total coil
resistance which suggests that the first coil in TABLE2 will
have the higher Q of the two  its radiating area is less than
3/4 that of the larger coil if the terminal size is taken into
account as well).
 As coil size increases (from table 1 to 3) the size of the
terminal required to make the coil resonate at the 1/4 wavelength
frequency increases also.
 My pick for highest power operation is the second coil in TABLE3.
Since a higher power throughput means longer sparks, the longer
coils will allow longer sparks before they show a preference for
striking the ground or primary strike ring. This coil will have
a better skin performance than the first coil in TABLE3.
 The large terminals not only allow a higher secondary voltage
before "letting go" if they have the largest possible radiusof
curvature for their capacitance but also a high discharge
current due to high capacitance (greater energy storage).
 The proximity of the terminal to the top of the coil is going
to affect these figures somewhat.
 The additional capacitance due to corona has been ignored in
this analysis. If an attempt is made to allow for additional
corona/ion cloud capacitance, I suggest a reduction in total
coil capacitance should be based on the intended operating
power level as this affects the amount of ionization. As power
level increases, total coil capacitance should be decreased.
 This last point conflicts with the normal practice of increasing
terminal size to get the best results at higher power levels.
Also as Richard has previously said, the coil compensates for
a lack of terminal size by forming a larger ion cloud. So at a
higher the power level, the larger the coil itself should be.
 Is it worth designing for 1/4 wavelength like this ? Given
that ionization can vary wildly it is debatable as the relation
holds only for one degree of ionization. For example, varying
spark length implies varying total secondary capacitance. The
nett effect of increasing capacitance is to reduce wire length
as the resonant frequency falls.
I did this analysis with a view to building a coil that would allow
a number of key experiments to be performed, including using terminals
with different capacitances but the same radiusofcurvature to determine
whether resonating the coil at, above, or below the 1/4 wavelength frequency
was critical to performance (this changes the capacitance distribution in
the system. It can also be viewed as effecting a change in the wirelength).
For a set amount of primary energy, the results will be clouded by the
increased primary L/C ratio needed to make the secondary resonate at lower
frequencies. This can be offset by reducing the coupling constant k as
primary inductance increases to keep the mutual inductance M constant.