> From mark.graalman-at-mediccom.norden1-dot-com
 > > From: richard.quick-at-slug-dot-org (Richard Quick)
 > > > From: bhaley-at-shore-dot-net (Brendan Haley)
> > BH> The question is:  the winding stops about 4 inches from the  
> > BH> top of the pipe.  There is one sweeping wind from the end of 
> > BH> the tight winding up to the top,  where the discharge        
> > BH> terminal is.  Does this spread out the capacitance along     
> > BH> this long wind, and away from the terminal. I have noticed   
> > BH> that there is corona all along this wind, and the sparks     
> > BH> seem to get stronger near the tight winding. 

> > BH> I am planning to cut off the rest of the pipe anyway,  but I
> > BH> am curious as to whether my intuition is correct (allthough  
> > BH> I doubt it)... Any kind responses are appreciated. Thank you
> > BH> -Brendan
>RQ >The only problems you are having is that: your discharger is
>RQ >mounted too high up off the top of the secondary winding; your
>RQ >discharger is too small in diameter; or both.

>RQ >Cut the coil form down to 1 inch above the winding, and properly
>RQ >cap the coil. I just use scrap pieces of squarely cut PVC pipe as
>RQ >insulating spacers to change and adjust the height of the
>RQ >discharger. 
> BH> Not to harp on the subject,  but why does the distance between the
> BH> winding and the discharger matter:  i.e.  what physical phenomenon is
> BH> occurring.  Is it extra resistance from the wire,  or capacitance? 
> BH> Normally I would envision the points as electrically equivalent, 
> BH> regardless of this length. 
> BH> I know I am wrong in assumming this,  and I am curious as to why.

> BH> Also,  while I'm asking,  what purpose does the discharger serve?  A
> BH> coil still produces the wireless power transmission without the
> BH> capacitive hat. 
 MG> Each ajacent turn in a coil makes a small capacitance, the top turn on
 MG> the secondary has no ajacent turn above it, so it will allow a corona
 MG> to occur if there is no terminal, or if the terminal is too high. The
 MG> terminal if it is large enough in capacitance, will become "dominate"
 MG> in comparision to the distributed/stray capacitity found in the coil
 MG> itself, thus it in effect draws the energy out of the coil, and
 MG> re-distributes the current in the secondary. The terminal also stores
 MG> the energy in between "bursts" and since the energy is stored
 MG> "outside" of the coil capacitance, it  increases the power handling
 MG> capability of the secondary coil. 

EXCELLENT ANSWER! Thanks for the input Mark. This is something that was
a little muddled in my mind, but your clarity here cut right through
the fog. I knew how it worked, I knew how to make it work better, but
you gave the best answer I have ever heard as to "WHY" it works.


Richard Quick

... If all else fails... Throw another megavolt across it!
___ Blue Wave/QWK v2.12