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Re: Power in TC system
Thanks Richie and Terry,
O.K, so the power can be given by:
P = 0.5* C*Bps* V^2
but the losses in the NST secondary and the rest of the system in
general should also be taken into account. Also the chaotic behavior
makes Bps a difficult parameter to nail.
So, the next questions are,
1) For a rotary gap what percent should I add to the power given in the
above formula as a "rule of thumb?"
2) For a static gap, again what percent could I add?
Again, thanks for your help,
Regards,
Gavin.