Re: Effective Resistance

["Jim Lux" <jimlux-at-jpl.nasa.gov> (by way of Terry Fritz <twftesla-at-uswest-dot-net>)]

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> From: Tesla list <tesla-at-pupman-dot-com>
> To: tesla-at-pupman-dot-com
> Subject: RE: Effective Resistance
> Date: Saturday, August 26, 2000 1:24 PM
> 
> Original poster: "John H. Couture" <couturejh-at-worldnet.att-dot-net> 
> 
> 
> Boris -
> 
> You may be right about Q factor and efficiency. However, I haven't
figured
> it out yet. The Reff in the Q factor equation means losses and
efficiencies
> involve losses but that would not be overall losses. How would you relate
Q
> and efficiency?
> 
> John Couture
> 

Since Q is just the inverse of the amount of energy lost per cycle (as a
ratio),  it should be pretty easy to relate efficiency and Q.  100%
efficiency = 0 loss = infinite Q.  Now, how are you going to define
efficiency?  As the amount of energy left in the tuned circuit after each
cycle?: In which case Q = 1/efficiency.....

A sort problem here is that your units are not consistent.  Efficiency
deals with a steady state power ratio (Pout = eff * Pin, or eff =
(Pin-Ploss)/Pin ), while Q is more of a transient effect relating to energy
stored in the tuned circuit.