Re: Maggies and such

["Malcolm Watts" <M.J.Watts-at-massey.ac.nz> (by way of Terry Fritz <twftesla-at-uswest-dot-net>)]

Hi Antonio,

On 16 Aug 00, at 8:02, Tesla list wrote:

> Original poster: "Antonio Carlos M. de Queiroz" <acmq-at-compuland-dot-com.br> 
> 
> Tesla list wrote:
> > 
> > Original poster: "sundog" <sundog-at-timeship-dot-net>
> 
> >     I am guessing that the secondary and tertiary coils have to be at the
> > same resonant freq.  Makes sense to me that they would be.  But will having
> > different inductances (a big fat driver with mediocre turns and a tertiary
> > that's wound with finer wire for more turns so they have the same res.
> > freq)..ideas?  I'm wanting to get the surge impedance down on the driver so
> > it can be coupled tighter.  Yep, gap losses go up, but this is for
> > examination more than long sparks.
> 
> An approximately correct relation is that the primary circuit must 
> resonate at the same frequency of the secondary+tertiary system.
> there is no important relation between the resonances of the 
> secondary and the tertiary.
> The relation, considering Inductances L1, L2, and L3 and
> capacitances C1 and C3 (ignoring the capacitance of the secondary)
> is: L1*C1=(L2+L3)*C3.
> But, as L2 has self-capacitance, this relation is never exact. C2 can
> be correctly taken into account with some additional complications,
> as I describe in:
> http://www.coe.ufrj.br/~acmq/tesla/magnifier.html
> 
> Antonio Carlos M. de Queiroz

Without looking at how you've done it I discovered that the 
following works well:

- calculate C2 (Medhurst)
- calculate C3 (    "   )
- sum Ctot = C2+C3
- sum Ltot = L2+L3

Fr = 1/[2.PI.SQRT(Ltot.Ctot)]

Regards,
Malcolm