See: http://en.wikipedia.org/wiki/Leakage_inductance Dave On 2/1/2014 4:24 PM, Jim Lux wrote:
The shunt results in large leakage inductance. Model it as a very large inductor in series with the secondary.For instance, if you have a 15kV, 30mA transformer, that implies that the series impedance of the secondary is 15E3/30E-3 or 5 Megohms. Using X = L *2*pi*f At 60 Hz, that's 13kHenry
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