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RE: [TCML] Cap Discharge Questions
Jim & Dave
Thanks both of you the light has finally come on with this one. I come from a Telecomm background where the standard test to see if the line was open circuit was a meter [set to ohms] across the line and then reverse it and watch for the phone's cap discharging through the meter. I was assuming without really thinking about it, that shorting the cap is the same, but the meter is of course putting a voltage reversal across the cap, to achieve that discharge. It was Dave's line of "How do the excess electrons on one plate of [CAP2] find their way thru the dielectric of [cap1] and [cap3]?" that done it for me.
I will rely on the primary L and short the spark gap instead (more reliable than transformer winding) and remember any work needs individual shorting in case of regained charge
This is my fourth MMC but it's the first time I have left them off, so I'm not in the habit of trying to defibrillate my own heart.
Regards
Phil
www.hvtesla.com
-----Original Message-----
From: tesla-bounces@xxxxxxxxxx [mailto:tesla-bounces@xxxxxxxxxx] On Behalf Of dave pierson
Sent: 20 January 2011 16:00
To: Tesla Coil Mailing List
Subject: Re: [TCML] Cap Discharge Questions
----- "Phil Tuck" <phil@xxxxxxxxxxx> wrote:
> Hello Dave,
> Thank you for the reply. Yes, I was referring to the individual caps.
> My old MMC of 216 caps had its bleed resistors twisted with the cap's
> lead wires, so when I rebuilt the MMC I had to cut the connections
> away, leaving too short a lead on the old cap for a new bleed
> resistor. The result is I now have 12 strings of 18 in series with no
> bleed resistors. I was going to use a resistive stick to discharge,
> and then keeping the stick in place, apply a link across the MMC to
> leave on for when not in use.
> So I presume (actually I am hoping) your reply of "No DC path from
> the 'inner' caps, round the loop, to equalize." Applies only if
> whatever was shorting the MMC (HV winding or stick etc.) is removed.
If i'm right (and i think i am....), without individual
bleeders, charge will stay stuck 'in' the series string...
> Let's say I have just three hypothetical, fully discharged, caps in
> series, like this:
> connection 'a' --- [CAP 1] --- connection 'b' --- [CAP 2] ---
> connection 'c' --- [CAP 3] --- connection 'd'
> I then apply 1000v just across CAP 2 using connection points 'b' &
> 'c'. Once the charge is removed I then connect, and leave connected, a
> resistance across all three caps at points 'a' & 'd' Will not the
> presence of the resistor and the outer caps provide a path for the
> middle cap to discharge?
I'd expect not. Simple solution: try it and see.
10 to 100VDC, and a hi z voltmeter should do
nicely.
> (I have never fully understood the mechanism that allows a cap to
> regain some of its charge.)
As i understand it:
1) thats quasi irrelavant to this discussion, mostly.
2) Assuming a single cap, for now: The charge in the
'plates' is 'imaged' by charges in the dielectric.
Being a dielectric, the imaged charges get 'stuck'
(cf: electrophorus). The surface portion
discharges, the remainder, over time, will 'diffuse'
to surfaces, appearing as remnant charge. (Some Years
back I was involved in high precision 'flying cap'
analog scanners/multiplexors & we needed to
account for this.)
Back to the series string of just capacitors:
I picture it this way:
Think of the individual electrons (lots) on
opposite plates of the center cap in the
string above. (OK: one plate has 'holes'.)
connect 'a' to 'd'. (zero ohms or resistor...)
How do the excess electrons on one plate of
[CAP2] find there way thru the dielectric
of [cap1] and [cap3]?
For AC(ish) voltages/currents (normal Tesla operation):
not an issue: AC couples thru the caps.
for any residual DC (the concern here?) SOME of the
charge will go in the transient when the connection
is made, however the (reduced) charge will remain
trapped on [CAP2], and even lesser on [CAP1] and
[CAP3]. The amount of charge/voltage on each will
be affected by the tolerance on the cap values.
repeatedly making the discharge connection will
remove 'some more, smaller' amount of charge
each time.
As I say: if a 100vish DC supply and a hi z meter be
handy, try and 'c'. (Presumably discharge thru an
_inductor_ would go into oscillation: THAT would
drain the charge(s) completely.)
best
dwp
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