On 16:59, jhowson4@xxxxxxxxxxx wrote:
Well Steve, experimental evidence and experience always supersedes
theory. Being an individual who wants to go into the field of high
voltage research upon graduation, I am going to have to play with
that software you have. =)
So I guess the real question is, where is the charge going? Since it
does not seem logical that a 50% decrease in surface area would yield
only a 10% -15% decrease in capacitance. So something else must be
going on here.
I suppose that the most logical explanation would be that charge is
actually being stored on the interior of the structure for these open
geometry designs. Maybe due to the incompleteness of the conductor
Faraday's law does not apply with the same rigor as it would in a
solid sphere model.
Charges in the interior of the structure are insignificant.
Practically all of it is just more concentrated on the exterior than
it would be in a solid surface, what leads to smaller breakout voltage
too.
Observe this simulation of the electric field around the wires of a
segmented toroid charged to 1 V. There is practically no field inside,
and no charge, and even the field on the wires at the inner part of
the toroid (right) is small.
http://www.coe.ufrj.br/~acmq/tesla/partialtoroid.gif
Antonio Carlos M. de Queiroz
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