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Re: [TCML] Terry Filter Resistors



Hey there guys, I have been following this thread since starting it and although my question was answered very early on I noticed that one of you offered plans off list for a home made wire wound resistor. As I am very interested in building my coil as much as possible (rather than buying pre made parts) I was wondering if it would be possible to send me these plans.

Thanks again in advance,

Simon
--
Simon Dodd
Director/ Technical Manager
Yes Boss Music
UK
simon@xxxxxxxxxxxxxxxx
www.yesbossmusic.com

On 29 Jan 2009, at 15:20, Lau, Gary wrote:

What are the dimensions of these resistors? My 6"x28" secondary coil's inductance is only 89mH, so 145mH seems huge. Granted, the resistor is wound with much finer wire with more turns, but it'll make an interesting sanity check to see how many turns a secondary wound to the same dimensions as your resistor would require to achieve 145 mH.

Regards, Gary Lau
MA, USA

-----Original Message-----
From: tesla-bounces@xxxxxxxxxx [mailto:tesla-bounces@xxxxxxxxxx] On
Behalf Of bartb
Sent: Wednesday, January 28, 2009 9:17 PM
To: Tesla Coil Mailing List
Subject: Re: [TCML] Terry Filter Resistors

Hey Gary, Matt,

Confirmed today at 145mH on todays reading (leads). Also measured 992
ohms. Measurements with 27XT.

I think Matt is correct and it's logical. If I do the math (noting that
the 27XT frequency is 1kHz):

Z = 145mH x 6.28 x 1kHz = 910.6 ohms.

XL = sqrt(992^2 - 910.6^2) = 394 ohms (note R-Z due to -sqrt).

L = 396 / (6.28 x 1kHz) = 62.7mH

Still significant, but then these are rather large wire wound resistors,
so not overly surprising.

Regards,
Bart


Gary wrote:
Please confirm "I just checked the resistor in question and it measured 146mH at
1kHz." 146 mH sounds about a million times too high for the inductance of a
wirewound resistor.

Matt wrote:
I think part of the problem is that most LC meters don't measure Inductance
directly. They actually measure the Z of the device and assume Z=XL, and therefore L=Z/2pif, which for most inductors is close enough. For a wire-wound resistor though, this is not a good approximation, since actually Z=sqrt(R2+XL2), and R is no longer negligible. You could use the L?shown by the meter to calculate what Z it actually read by Z=2pifL, then using the known resistance, calculate a corrected XL? from XL=sqrt(Z2-R2)and from that, determine the corrected L by
L=XL/2pif.

Matt D.

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