OK, looking at Terry's paper, I see the waveform you refer to. The Peak secondary base current is 5 Amps, not 10. But I think you may have an incorrect understanding of RMS current. If one has a _continuous_ sine wave with a peak current of 10 Amps, the RMS current is 7.07Amps. But as you know, the secondary current in a disruptive coil is not continuous. It has a low duty cycle of something roughly like 1%, and even during the bang-time, the amplitude envelope is very complex. There is no simple conversion between the 5A peak current in Terry's waveform, and the RMS current. The BPS, coupling, and quench time all factor heavily into the RMS current. There are ways to measure RMS current, the best being with a digital scope that does a lot of number-crunching over a time interval that includes both the bang on and off times. Measuring the brightness of an incandescent bulb also works, because it has a sufficiently long thermal time constant to kind of average the current over the bang on and off times. But the key is that you need to look at a waveform over a time interval where it repeats. That's how a waveform with a peak current of many Amps can have an RMS value in the mA range. You can't just look at the peak value and deduce the RMS value. It's the RMS current that correlates to how much wire heating will occur. If you're writing tools that purport to give RMS results, it's important to understand what that means.