Re: calculating copper plate indutance (fwd)

["Tesla list" <tesla@xxxxxxxxxx>]

---------- Forwarded message ----------
Date: Sun, 23 Sep 2007 19:24:42 +0100
From: Chris Swinson <list@xxxxxxxxxxxxxxxxxxxxxxxxx>
To: Tesla list <tesla@xxxxxxxxxx>
Subject: Re: calculating copper plate indutance (fwd)

Hi Bart,

No, there is nothing in the box whatsoever not even a zero. I did try 100 
turns and still nothing.

The resistances are less than 10 milliohms I would imagine. I am only using 
a single turn of thick sheet so it should work out like 1 milliohm..

Cheers,
Chris



----- Original Message ----- 
From: "Tesla list" <tesla@xxxxxxxxxx>
To: <tesla@xxxxxxxxxx>
Sent: Sunday, September 23, 2007 7:03 PM
Subject: Re: calculating copper plate indutance (fwd)


>
> ---------- Forwarded message ----------
> Date: Sun, 23 Sep 2007 10:40:01 -0700
> From: Barton B. Anderson <bartb@xxxxxxxxxxxxxxxx>
> To: Tesla list <tesla@xxxxxxxxxx>
> Subject: Re: calculating copper plate indutance (fwd)
>
> Hi Chris,
>
> Let me guess; you are seeing 0 in the resistance box? Ok, this is
> exactly why I said more precision past 3 decimal places. Just change
> your turns to like 100 and see what happens.
>
> I can always change the output to milliohms as this might make more
> sense for flat ribbon primary's. I should have done that from the start.
> Ok, I'm off to do that. Should only take me a couple minutes.
>
> Take care,
> Bart
>
> Tesla list wrote:
>
>>---------- Forwarded message ----------
>>Date: Sun, 23 Sep 2007 16:01:09 +0100
>>From: Chris Swinson <list@xxxxxxxxxxxxxxxxxxxxxxxxx>
>>To: Tesla list <tesla@xxxxxxxxxx>
>>Subject: Re: calculating copper plate indutance (fwd)
>>
>>Hi Bart,
>>
>>Thanks for taking the time to add it in!
>>
>>I can't get anything to come up in the resistance box though ?
>>
>>Cheers,
>>Chris
>>
>>
>>
>>
>>
>>>Hi Chris,
>>>
>>>I added copper ribbon resistance to the output as requested.
>>>http://www.classictesla.com/java/flatribbon/flatribbon.html
>>>
>>>I've got it set to 3 decimal places. If your looking for more precision
>>>for small turns, you can always calculate it.
>>>R=pL/A where p is resistivity of material, L is the length, and A is the
>>>cross sectional area.
>>>
>>>So, A = thickness x height
>>>L = Length of winding
>>>p = 0.000001678 ohms/cm (the number I'm using anyway)
>>>
>>>The resistivity of copper varies. This is part of the problem with
>>>resistance numbers. There are a lot of copper alloys and even processes
>>>can change affect resistivity. Temperature is also a large factor. The
>>>output value will assume a temp of 20C (68F) and the common resistivity
>>>number shown above.
>>>
>>>Take care,
>>>Bart
>>>
>>>
>>>
>>>>Would it be possible to mash the resistance calculation into that too ,
>>>>pretty pleaseeee ;o)
>>>>
>>>>Chris
>>>>
>>>>
>>>>
>>>>
>>>
>>>
>>>
>>
>>
>>
>>
>>
>>
>>
>>
>
>