Original poster: <davep@xxxxxxxx>
>...rectenna...
I shorthanded, perhaps confusingly.
As noted, the rectenna, itself is quite
conventional. I referred to the downlink source.
>inverse square for a 'well collimated' beam.
Skipping for the moment the engineering detail of how to,
I tend to wonder where the energy goes, in the _specific_
hypotehtical, case.
How does a well collimated beam differ, eg, from a
waveguide guided beam?
(skipping, for discussion purposes, absorption losses in
waveguide case...)
Or we may be getting too far OT?
Feel free to drop.
best
dwp