Re: Quick Questions

["Tesla list" <tesla@xxxxxxxxxx>]

Original poster: robert heidlebaugh <rheidlebaugh@xxxxxxxxxxxxxx>

Ian Lacey ;The problem is your microscopic view. Step back an look .
      The TC is a air core transformer with a high voltage and a primary
secondary torns ratio . If the primary is one turn the  and the secondary is
one turn the output will be the same as the input less losses. This dose not
consider the resonance.
 only the ratoi ( except for ED's theory) The wave shape has littel if any
effect. Now if we add resonance  The output of the system is dependent on
the Q of the circuit and the output wave shape is sinusodial as the
secondary resonates ,not square wave as the input may be. The pulse width of
the input dose change the total power transphered but not the voltage. The
brialience of the spark will change and may not be seen if to littel power
is transphered but the voltage is still volts in x ratio less losses times
resonance effect. Before breakout,  losses can be very low and the resonance
effect can give you 4x boost in voltage (not power). When I used 2wo 5 ft
dia spheres I could get over a mega volt beforer carona discharges would
limit my voltage. My limitations were insulation and humidity but the Abs
humidity in Wyoming in winter is very low at -50 o F.
     Robert   H
--


> From: "Tesla list" <tesla@xxxxxxxxxx>
> Date: Thu, 10 Nov 2005 08:58:02 -0700
> To: tesla@xxxxxxxxxx
> Subject: Re: Quick Questions
> Resent-From: tesla@xxxxxxxxxx
> Resent-Date: Thu, 10 Nov 2005 09:02:16 -0700 (MST)
>
> Original poster: Jim Lux <jimlux@xxxxxxxxxxxxx>
>
> At 08:07 PM 11/9/2005, Tesla list wrote:
>> Original poster: Ian Lacy <ianlacy@xxxxxxxxx>
>>
>> Hey all,
>>
>> My name is Ian and I am currently an undergraduate at the University
>> of Kansas. In my secondary circuit analysis course we're using
>> function generators and oscilloscopes to analyze the RMS values and
>> effective voltages. The experiment was very straight forward and I
>> found myself wanting to know more as the material was not covered in
>> depth. I subscribe to this mailing list and read it often because I
>> find it educational and fascinating. I find myself hesitant to reply
>> to most of the posts because my level of knowledge on the subject is
>> very minuscule comparatively. This is why I've decided to present my
>> questions to this group. Perhaps some will be able to help?
>>
>> Why exactly do frequency and the duty cycle of a square wave have no
>> effect on the V RMS value?
>
> RMS value is the square root of the mean squared value.  A square
> wave (if symmetric around zero volts), when you square it, is
> constant, so the squared value is constant, so the mean of the
> squared value is constant, etc...
>
>
>> Also, how does the DC offset effect the power of the signal?
>
> A DC offset increases the RMS value and does make the RMS value
> sensitive to the duty cycle.
>
> In any given cycle, with duty cycle "D"...(from 0 to 1)
>
> For D amount of time the DC value is Offset+PeakToPeakValue/2
> For 1-D amount of time, the DC value is Offset - PeaktoPeakValue/2
>
> the squared value for the first one is (offset+PP/2)^2 or offset^2 +
> offset*PP + PP^2/4
> for the second, offset^2 - offset*PP + PP^2/4
>
> The mean of the squared values is then:
> (D+ (1-D)) * offset^2
> + D * offset*PP
> + (1-D) * -offset*PP
> (D+(1-D)) * PP^2/4
>
> collecting and cancelling:
> offset^2 + PP^2/4 + (D - (1-D)) * offset*PP
> =offset^2 + PP^2/4 - (2*D - 1) * offset*PP
>
>
>
>
>> Thank you,
>>
>> Ian Lacy
>> The University of Kansas
>> Theta Tau, Z'996
>> IEEE Student Member
>
>
>