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Re: PFC Question
- To: tesla@xxxxxxxxxx
- Subject: Re: PFC Question
- From: "Tesla list" <tesla@xxxxxxxxxx>
- Date: Thu, 03 Nov 2005 21:09:01 -0700
- Delivered-to: chip@pupman.com
- Delivered-to: tesla@pupman.com
- Old-return-path: <vardin@twfpowerelectronics.com>
- Resent-date: Thu, 3 Nov 2005 21:09:43 -0700 (MST)
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- Resent-sender: tesla-request@xxxxxxxxxx
Original poster: "Gerry Reynolds" <gerryreynolds@xxxxxxxxxxxxx>
Hi Ed,
The pig is close to an ideal transformer and the impedance it
presents at its input is a reflection of the load impedance it is
driving (a short when the SG fires, a capacitance when the TC caps
are charging). If Cp is LTR, the impedance of the ballast will
dominate and the impedance presented to the variac will look
inductive. This is why the PFC caps need to be in parallel with the
combined load the ballast and pig presents. The PFC caps only
correct for inductive loads. If you are running the pig with a STR
Cp value, then PFC caps wont work cause the load presented to the
variac will be capacitive (maybe a PFC inductor will help here). PFC
caps can also be placed upstream of the variac as well to correct for
the inductance added by the variac itself. However, the variac
inductance will be a function of the variac setting (zero inductance
when variac_out = variac_in)
You can calculate the PF (without PFC) by taking the TC Cp and
transforming it to the primary of the pig (multiply the Cp by N^2 to
get lower capacitive reactance at the pig primary). You can figure
the resulting reactance from the combination of the ballast inductive
reactance and the capacitive reactance at the pig input. Use this
resulting reactance with an equivalant resistance in series with it
where the resistance will model the real power draw (bps * bang energy).
Gerry R.
Original poster: Esondrmn@xxxxxxx
Does anyone know or venture to guess how far off the power factor is
on this kind of set up. The transformer is primarily an inductive
load, but does some of that get canceled by