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Re: Streamer V/I and energy balance
- To: tesla@xxxxxxxxxx
- Subject: Re: Streamer V/I and energy balance
- From: "Tesla list" <tesla@xxxxxxxxxx>
- Date: Sat, 23 Jul 2005 17:44:50 -0600
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Original poster: Terry Fritz <teslalist@xxxxxxxxxxxxxxxxxxxxxxx>
Hi Marco,
I summed E = SUM(V(t) x I(t))dt as you did too and got this:
http://hot-streamer.com/temp/Marco031.gif
From my little test:
http://hot-streamer.com/temp/Marco-001.gif
http://hot-streamer.com/temp/DaveTest-57.jpg
Not sure what it means but maybe the drop in your energy at the end
is some oscillations or something to do with a lower band width. In
my high bandwidth case, I get a lot of ripple, but the power ends up
the same at the end as the first peak.
Cheers,
Terry
At 02:35 PM 7/23/2005, you wrote:
Hi all,
I did try to model with MicroSim the streamer 000 (see my previous
postings and Terry's http://hot-streamer.com/temp/Marco12.pdf). I
got nowhere. In practice a negative resistance component is needed,
with some extra features for the streamer breakdown (high current)
threshold simulation. Need to spend more time on that.
But then I used Matlab to compute the streamer energy (the bang was
a 12.8 J). I got what you can see at:
http://www.iki.fi/dncmrc/scratch/str_energy.gif
Vertical scale is 135.4 kV/V, 10 A/V or Joules.
Energy (in red) peaks to 6.6J but then goes down to 5.7J!
How's that? V and I are really of opposite polarity during that
interval of time but how?
Regards