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Re: DIY HV transformer
- To: tesla@xxxxxxxxxx
- Subject: Re: DIY HV transformer
- From: "Tesla list" <tesla@xxxxxxxxxx>
- Date: Thu, 14 Jul 2005 17:23:48 -0600
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- Delivered-to: tesla@pupman.com
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- Resent-date: Thu, 14 Jul 2005 17:23:57 -0600 (MDT)
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Original poster: Rob Maas <robm@xxxxxxxxx>
Tesla list wrote:
Original poster: Steve Conner <steve@xxxxxxxxxxxx>
> I removed the center leg, use one original winding
> as 160 turns primary and
> on the opposite side there sits the HV coil I wound.
Christoph,
This seems to make good sense to me. You could put a
laminated iron shunt into the space where the centre
leg was. So you could have a HV transformer and
ballast choke in one unit. Did you keep the centre leg
when you sawed it off ;)
If you were feeling adventurous you could maybe try
making an adjustable shunt similar to what is used in
arc welders.
Steve Conner
Steve,
I measured the coupling coefficient k of one of my MOT's: k = 0.985
The width of the magnetic shunt in this MOT is 4 mm; the width of the
centre leg is 4 cm, so the ratio (shunt area)/(centre leg area) = 10%.
In this MOT this ratio produces a k = 1 - 0.015 = 0.985
Now suppose I want a k value of k = 0.95 (which is a 'typical' value
of k in a NST). The question is now: what value of the above ratio will
produce this k? Is it (0.05/0.015)*10% = 33 %, or goes it with a SQRT
(i.e. 18 %)?
Do you, or anybody of this list, know the procedure how to calculate this?
regards, Rob