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Re: Streamer modeling

Original poster: "Gerry  Reynolds" <gerryreynolds@xxxxxxxxxxxxx>

Hi Terry,

I like your approach of seeing how much the capacitance needs to increase to keep the voltage from getting above breakout and then computing the streamer length from this delta C. Seems much easier than trying to determine the streamer size needed to absorb the excess charge and then computing the capacitance from the streamer size.

At some point, Im thinking, the breakout voltage reduction might want to be included (assuming that it does indeed get reduced). I would think that the further the streamer gets from the top load, the more the breakout voltage (Vbo) would be reduced. For short streamers, I would think the size of the topload would shield the streamer and the presence of the streamer would have lesser affect on the E field for a given voltage. The further the streamer is from the topload, the more the geometry of the streamer would increase the E field given the same voltage (or reduced Vbo given a constant E field of 3MV/m). Comments welcomed.

Gerry R


Original poster: Terry Fritz <teslalist@xxxxxxxxxxxxxxxxxxxxxxx>

I am testing
now a version of the calculation engine where the capacitances and resistances
can change. The present model for the streamer load, C2 (part), R3, and C3,
can then be made to change to simulate breakout and streamer growth.
The problem is how they change. In a first approximation I am trying to
leave R3 constant and increasing C2 and C3 when the terminal voltage
exceeds a certain breakout voltage, by equal amounts that return the terminal
voltage to about the breakout voltage.

C2 should "really" never change... I try to mess only with C3... Maybe make an arm waving "corona capacitance" and stuff ;-))

The result is that the load capacitance
increases at the voltage peaks, and more power is dissipated in the fixed
streamer resistance R3. Detuning limits the increase at some point.
If this makes sense, streamer length can be estimated by the increase in
the streamer capacitance.


Ok :-))  I don't know at this point ;-))

Cheers,

Terry