[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
RE: 3 phase converting
- To: tesla@xxxxxxxxxx
- Subject: RE: 3 phase converting
- From: "Tesla list" <tesla@xxxxxxxxxx>
- Date: Sat, 22 Jan 2005 10:13:55 -0700
- Delivered-to: testla@pupman.com
- Delivered-to: tesla@pupman.com
- Old-return-path: <teslalist@twfpowerelectronics.com>
- Resent-date: Sat, 22 Jan 2005 10:17:38 -0700 (MST)
- Resent-from: tesla@xxxxxxxxxx
- Resent-message-id: <xO-7UD.A.KpF.yqo8BB@poodle>
- Resent-sender: tesla-request@xxxxxxxxxx
Original poster: Harvey Norris <harvich@xxxxxxxxx>
--- Tesla list <tesla@xxxxxxxxxx> wrote:
> Original poster: Jim Lux <jimlux@xxxxxxxxxxxxx>
> However, say you have two coils and you want the
> phase of the current
> through one to be 90 degrees away from the phase of
> the other. Could you
> not just put an appropriate capacitor in series with
> the one coil. Say
> that the coils have an impedance of R+jX..
>
> Make sure that R = X...
>
> You'd put a capacitor of impedance -j2X in series,
> so one leg would have
> impedance R+jX and the other would have impedance
> R-jX. Since R=X, the
> current through one coil will be lagging the voltage
> by 45 deg, and the
> current through the coil with the capacitor will be
> leading by 45 deg,
> hence 90 degrees apart.
>
> If the inductance is large compared to the
> resistance, then a capacitor of
> just -jX should work. If R<<X, then current through
> one coil is 90 degrees
> lagging, and the current through the other coil will
> be in phase.
>
> If you want balanced currents, you might need to
> fiddle a bit with Ls and
> Cs to get the phases and amplitudes right.
In the case where the reactance is cancelled by -jX,
there will be a voltage rise given by the acting q
factor. To obtain equal currents on both coils it
would be necessary for the reactive side to be inputed
from a transformer that delivered a voltage equivalent
to that made by the resonant side. Hence the reactive
side becomes very innefficient compared to the
resonant, as it takes q times more amperage on that
branch to accomplish the same amount of magnetic flux.
HDN