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Re: Meter Shunts ??
- To: tesla@xxxxxxxxxx
- Subject: Re: Meter Shunts ??
- From: "Tesla list" <tesla@xxxxxxxxxx>
- Date: Mon, 14 Feb 2005 19:53:10 -0700
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- Delivered-to: tesla@pupman.com
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- Resent-date: Mon, 14 Feb 2005 19:54:03 -0700 (MST)
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Original poster: <tesla@xxxxxxxxxxxxxxxxxxx>
the 0-350VDC is easy, you can get direct readout meters for this, You'd
probably need a 500 volt model.
500amps DC will need a large shunt. It's probably going to be brass and
weight a few pounds. You don't need a resistor for this part though. Just
get a meter with the front labelled Amps and the coil needing 50mV or
whatever your shunt is rated. the heavy current goes though the shunt, not
the meter. If you can get the correct meters, you don't need any resistors
for this.
http://www.meterdistributor.com
has nice pictures and info on meters and shunts. You can usually mix and
match the parts (meter/shunt or meter/current transformer).
KEN
> Original poster: Thomas DeGregorio <tommacs@xxxxxxxxxxxxx>
>
> Oh I'm talking about voltages anywhere from zero volts to 350VDC.
> Then current anywhere from 0 to oh say about 500amps.
> Then of course I would like to do primary measuring so then 15KVAC
> but that's a different story.
>
> I just wanna to know if using resistors is an efficient way of
> dropping the current and voltage since it will be to high for the meter to
> handle. I have found a nice cheap 200 amp panel meter, I so can just use a
> resistor so it can handle more current and drop the voltage, then just
> recalculate that new ratio and then I know what the current is. Then do the
> same with a voltage panel meter though I will need to get one that reads
> like mVDC since I will need a big meaty resistor.