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Re: Meter Shunts ??

Original poster: Thomas DeGregorio <tommacs@xxxxxxxxxxxxx>

Oh I'm talking about voltages anywhere from zero volts to 350VDC. Then current anywhere from 0 to oh say about 500amps.
Then of course I would like to do primary measuring so then 15KVAC but that's a different story.

I just wanna to know if using resistors is an efficient way of dropping the current and voltage since it will be to high for the meter to handle. I have found a nice cheap 200 amp panel meter, I so can just use a resistor so it can handle more current and drop the voltage, then just recalculate that new ratio and then I know what the current is. Then do the same with a voltage panel meter though I will need to get one that reads like mVDC since I will need a big meaty resistor.


On Feb 14, 2005, at 9:25 AM, Tesla list wrote:

Original poster: robert heidlebaugh <rheidlebaugh@xxxxxxxxxxxxxx>

An additional comment, In old radio transmitters the current meter was
mounted recessed behind the front panel a inch or so to protect finger
meter readers from high voltage as the meter was at high voltage potential.
      Robert   H
--


> From: "Tesla list" <tesla@xxxxxxxxxx>
> Date: Sun, 13 Feb 2005 19:51:56 -0700
> To: tesla@xxxxxxxxxx
> Subject: Re: Meter Shunts ??
> Resent-From: tesla@xxxxxxxxxx
> Resent-Date: Sun, 13 Feb 2005 19:52:24 -0700 (MST)
>
> Original poster: Ed Phillips <evp@xxxxxxxxxxx>
>
> "A shunt is nothing more than a low value resistor. Current through the
> shunt
> causes a voltage drop across it such that V = I x R.
>
> Stephen A. Mathieson"
>
> It's quite a little more than that.  Most importantly, its a 4-terminal
> resistor!  Heavy current flows through the main terminals while the
> meter is connected to a second pair of terminals.  That way contact
> resistance is minimized and any connection resistance in the
> high-current circuit has no effect on the reading.
>
> Ed
>
>