Original poster: Mddeming@xxxxxxx
Hi Ed,
Actually since he is dividing by 5/9, he is correct. It would
be equivalent to multiplying by 9/5. (centigrade*(9/5)+32) is the
same as (centigrade/(5/9)+32). It confused me for a minute too.
Matt D.
In a message dated 12/5/05 6:15:49 P.M. Eastern Standard Time,
tesla@xxxxxxxxxx writes:
Original poster: Esondrmn@xxxxxxx
Bart.
A typo I suspect. Centigrade to Fahrenheit should be:
To convert from Centigrade to Fahrenheit: (centigrade/(9/5)+32)
9/5 as opposed to 5/9.
Ed Sonderman
In a message dated 12/4/2005 5:57:43 PM Pacific Standard Time,
tesla@xxxxxxxxxx writes:
Original poster: "Barton B. Anderson" <bartb@xxxxxxxxxxxxxxxx>
Hi All,
I updated Javatc with a minor update (just a clean-up item)
http://www.classictesla.com/java/javatc.html
At the top of the form there is a new input box for Ambient
Temperature and drop down for Centigrade or Fahrenheit. The default
is 68 Fahrenheit (20 Centigrade). This effects only the DC Resistance value.
The download version is also upgraded and available at the web site.
For those who are interested, the equation for DC resistance with
ambient temp considerations:
DCR = ((4 x (wire length) x 6.787 x 1e-7) / ((wire diameter)^2 x PI))
x (1 + (C-20) x 0.0039)
where
DCR = DC Resistance in ohms
wire length & wire diameter = inches
C = degrees Centigrade
PI = 3.14159....
Temp Unit conversion:
To convert from Fahrenheit to Centigrade: (fahrenheit-32)*(5/9)
To convert from Centigrade to Fahrenheit: (centigrade/(5/9)+32)