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Re: just wondering (Schumann resonance)
Original poster: "Dr. Resonance" <resonance-at-jvlnet-dot-com>
Tesla's "death ray" worked on a totally different principle. It used a
large electrostatic generator to accelerate small particles to very high
velocity. In principle, this might have worked.
You're right on the Schumann resonance --- high loss factor and attenuation
of signal.
Dr. Resonance
> I have a couple of thoughts about the Schumann resonance.
>
> As a radio ham I know about propagation and stuff. And I understand the
> Schumann resonance is a standing wave caused by a radio wave that, in
> wavelength terms, fits exactly once (or a whole number of times) round the
> earth. (please correct me if I'm wrong.)
>
> Now, if my "standing wave" analogy is correct, I would imagine the
> propagation path for the wave that forms the Schumann resonance is pretty
> lossy. When talking to very high powered foreign stations on the HF band,
I
> could often hear a distinct "echo" on their signal, which is of course
> caused by their radio waves reaching me twice, the short way round the
> world, and the long way.
>
> Anyway, from observations like these, I would estimate the loss for a trip
> round the world is over 100dB. I was working at 10s of MHz, it would of
> course be lower at the 10s of Hz where the Schumann resonance happens. But
> even assuming the loss goes down in proportion to the frequency, it's
still
> a 40dB loss (40dB= 1/10000) at 10Hz.
>
> So how on earth you could ever excite a resonance in such a lossy system,
> using even the most powerful transmitter ever made, I don't know.
>
> If these loss figures are ballpark, it blows all that "wireless death ray"
> cr*p out the water too: For instance, Tesla couldn't have caused the
> Tunguska explosion ;) without causing an explosion 40dB bigger at his
> transmitter site, and I think folks would have noticed New York missing
:)))
>
> Steve C.
>
>
>