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RE: TC Spark Energy
Original poster: "John H. Couture" <couturejh-at-mgte-dot-com>
Malcolm -
Note that it is the energy in the spark that we are after not voltage.
Efficiency = energy out/energy in
The problem is to find the energy to produce a spark of a certain length
with a certain TC of a certain design.
John Couture
-----------------------------
-----Original Message-----
From: Tesla list [mailto:tesla-at-pupman-dot-com]
Sent: Thursday, March 11, 2004 9:27 AM
To: tesla-at-pupman-dot-com
Subject: RE: TC Spark Energy
Original poster: "Malcolm Watts" <m.j.watts-at-massey.ac.nz>
On 10 Mar 2004, at 17:00, Tesla list wrote:
> Original poster: "John H. Couture" <couturejh-at-mgte-dot-com>
>
>
> Dr. Resonance -
>
> As you know the topic of TC spark energy has been discussed before on
> this List. Little progress was made because of the confusion over the
> difference between power and energy. The TC spark energy test is very
> simple, only an input wattmeter and tape measure are required. The
> operation is continuous and the same as typical TC operation. Just add
> a wattmeter at the input and measure the spark length.
>
> Because the operation is continuous the wattmeter (power) indicates
> watts per second (energy). All you need is the number of sparks per
> second to find the number of watts seconds or energy per spark. The
> number of equal sparks per second is not an easy number to come by.
> However, it can be determined provided the coiler adjusts the TC spark
> output to give 120 equal spark lengths per second (for 60 Hz). The
> spark should be horizontal and to a suitable ground.
>
> In my test I adjusted the variac to get a continuous wattmeter reading
> of 120 watts or watt seconds. The sparks were adjusted until the spark
> was continuous and of equal length at 120 sparks per second. Energy =
> watt seconds = joules.
>
> Joules per spark = 120 joules/120 sparks = 1 joule per spark
>
> The spark length was measured and found to be 8.5 inches. This then
> gave me a Tesla coil rating for my Tesla coil of 8.5 inches per joule
> of energy.
>
> It is obvious from the above that if the wattmeter had indicated 175
> watts with a 10 inch continuous spark and at 90 sparks per second the
> TC would be rated
>
> 175/90 = 1.94 joules per spark
>
> 10 inch/1.94 = 5.16 inches per joule.
>
> This TC would have been less efficient because it is producing less
> spark length per joule of input energy. All very simple. So why is it
> that coilers have seldom rated their TCs this way?
Because the length of spark per JOule is highly dependent on the coil
design. Pumping 1J into a high-C secondary is not going to give the
same sparklength as pumping 1J into a low-C one is it? Just for
starters, the output voltages will be quite different.
> The answer is also very simple. This rating method gives low ratings
> for large TCs, only a couple inches per input joule. In other words
> large TCs appear to be very inefficient. This is a problem. Any
> comments?
I fail to see what the voltage developed by 1J into a small
capacitance vs the voltage developed by putting 1J into a large
capacitance has to do with efficiency.
?
Malcolm