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Re: THOR Bang energy vs. streamer length measured
Original poster: "Gerry Reynolds" <gerryreynolds-at-earthlink-dot-net>
Hi Marco,
> Original poster: "Denicolai, Marco" <Marco.Denicolai-at-tellabs-dot-com>
> I believe there is a MINIMUM BPS to achieve the top streamer length (for
> the SAME primary capacitor voltage, i.e. bang energy). The rise in
> length is very steep vs. the BPS. This minimum BPS ought to be below 200
> Hz (IMHO). Above this BPS value the streamers just grow intensity (more
> "fat") or happen slightly more often.
> Now you can call that minimum BPS value an optimum. It is an optimum as
> it maximizes the length for the minimal average power fed.
OK, I can see where you are going. The question I was wanting to answer
will probably come out of your experimentations.
> > If one has a fixed power source, it seems that one want to
> > find the optimum BPS for that source which is a different experiment?
>
> No, it is a subproblem.
> The fact is simply that if you want to detect the influence of factors A
> and B on result C, it doesn't help to variate both A and B and measure
> C. You can't discern which of A or B affected C's change. There is a
> whole discipline called "experimental design" devoted to this problem.
> In a nutshell, following the KISS principle, change A keeping B
> constant, measure C. Then change B keeping A constant, measure C.
I agree this needs to be done first. My thinking (along the lines for
rotary systems) was that given a power source, you use the maximum Cp that
it will charge (maximize the bang), then the only variable left is BPS.
I think a whole family of curves are needed not just a two axis probe (and I
think this is what you are doing) cause there may be a non linear
interactions between A and B.
> After collecting this family of measurement you can combine them as C =
> f(A,B). From that you can transform into your subproblem of maximizing C
> (the length) vs. A*B (the product of energy and BPS, the average power).
Keep talking, I will keep listening, and I do appreciate the tremendous
effort your experiment is taking :-))
Best Regards,
Gerry R.