Re: Resonant Voltage Formula

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Antonio Carlos M. de Queiroz" <acmdq-at-uol-dot-com.br> 

I wrote:

 > > Original poster: "Steve Conner" <steve.conner-at-optosci-dot-com>
 > >
 > >  >The quantiti [pi/Q] in "Vpeak = Vmax(1-exp(-n*pi/Q))" is known as the
 > >  >"logarithmic decrement" of the waveform.
 > >
 > > The original poster was not asking about how the waveform decays 
naturally,
 > > but how it rings _up_ when the resonance is forced by a SSTC-like 
driver. I
 > > must admit that I don't know a simple formula for this one :(
 >
 > This is exactly the formula for "ring up". The formula for "ring down"
 > is Vpeak = Vmax*exp(-n*pi/Q).

Hummm. Really, the expression for ring-up is more complex, because there
is the forced response to the input signal added to a transient
response.
But the formula above gives a good approximation when Q is high and the
excitation frequency is close to the resonance frequency of the network.

Vmax=Q*Vin in the expression.

Antonio Carlos M. de Queiroz