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Re: Ideal Magnifier Model - PSPICE (Antonio?)
Original poster: "Antonio Carlos M. de Queiroz" <acmq-at-compuland-dot-com.br>
Tesla list wrote:
>
> Original poster: Rob Maas <robm-at-nikhef.nl>
> >Lumped model of a "Tesla magnifier":
> > k12
> >+----+ +----+--L3--+---o output
> >| | | | |
> >C1 L1 L2 C2 C3
> >| | | | |
> >+----+---+----+------+---o ground
> >
> >C2="self-capacitance" of L2 + "self-capacitance" of L3 + "transmission
> >line" capacitance + other capacitances to ground at that point"
> >(+ guessing factor, since all this is approximate).
>
> Why is the "self capacitance of L3" included in C2:
We usually model a coil that has distributed capacitance and one side
grounded as a grounded coil in parallel with a "self-capacitance",
grounded too.
In a magnifier, the third coil has both ends floating. If we assume that
the capacitances from both ends of the coil to ground are identical,
the simplest model for a floating coil has then a capacitor to ground at
each end:
+--L3--+
| |
C3a C3b
| |
+------+-o ground
If one end of the coil is grounded, if we assume that the
capacitances don't change due to this, the two capacitors must be
each identical to the "self-capacitance" of the coil.
And really, a measurement (or calculation) of the free-space
capacitance of a cylinder results in a capacitance that is quite
close to twice the Medhurst capacitance for a coil with the
shape of the cylinder.
Example: A coil with 32 cm of length and 4.4 cm of radius has a
Medhurst capacitance of 5.55 pF.
The free-space capacitance of an open cylinder with these dimensions
results as 10.15 pF.
> Isn't C3 = 'self capacitance of L3' + 'capacitance of topload' on top of
L3 ?
Yes, it is, using the "normal" copy of the self-capacitance at the
output side of L3.
Antonio Carlos M. de Queiroz