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Re: Flat transmission line capacitance formula?
Original poster: "Antonio Carlos M. de Queiroz" <acmq-at-compuland-dot-com.br>
Tesla list wrote:
> Original poster: Bert Pool <bert.tx-at-prodigy-dot-net>
>
> I have formulae for isolated spheres, toroids, flat plate capacitors, etc.,
> but do not have a formula for calculating the capacitance of a single, long
> flat plate transmission line. I use a long strip of aluminum flashing for
> the transmission line from the driver to the extra coil on my
> magnifier. Tesla provides us a formula for a cylindrical transmission
> line, but nowhere do I find a formula for a flat plate line. Does anyone
> out there have such a formula? I will be conducting some measurements on a
> real-world line to determine the measured capacitance, but it sure would be
> a help if I had a starting formula from which to work!
A formula for the capacitance per unit of length for a cylinder above a
ground plane is known:
C/length=4*Pi*e0/(2*Ln((h+sqrt(h^2-a^2))/a))
Where h is the height above ground of the center of the cylinder and a
is
its radius.
For a flat strip above ground, I don't know a closed expression, but
it seems to be a good approximation to consider the strip as a cylinder
with radius equal to 1/4 of the width of the strip, if it is far enough
from the ground.
Running a simulation with the Inca program:
I can describe a flat 10 cm strip making a wide (1 m) loop 20 cm above
a ground plane, having at the other side of the plane a thin toroid, for
comparison, as:
* Transmission line
L top 50 0.95 0.2 1.05 0.2
L ground 100 0 0 1.5 0
C other 50 1 -0.2 0.025 0 360
.v ground 0
The program calculates the capacitances as:
C[top,top]: 123.6100741149 pF <-------
C[top,ground]: -108.9185608288 pF
C[top,other]: -0.9406758383 pF
C[ground,ground]: 300.4595813461 pF
C[ground,other]: -109.8495626018 pF
C[other,other]: 124.4980846604 pF <-------
The indicated values are the capacitances of the flat strip and of the
toroid, considering the other elements grounded.
The capacitance of a cylinder with length 2Pi m, 0.2 m above ground,
and with radius of 0.025 m would be, by the formula:
C=2*Pi*4*Pi*e0/(2*Ln((0.2+sqrt(0.2^2-0.025^2))/0.025)) = 126 pF
The precision of the approximation seems to be as good as measurements
can be.
Antonio Carlos M. de Queiroz