Re: Please help with capacitor

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Philip Brinkman" <peeceebee-at-mindspring-dot-com> 

   Wow, thanks Gerry, I will aim for 16 nf. I recalculated, and my plates
have 1.008 nf each, so I will only need 16 or 32 plates ! I don't know if
the calculation is for 2 plates or one. Does anyone know how that formula
works? C=eA/d, does that  area A include the total area of two plates, or
the area of just one of the two plates separated by distance d .... my
brain hurts.!!


 > [Original Message]
 > From: Tesla list <tesla-at-pupman-dot-com>
 > To: <tesla-at-pupman-dot-com>
 > Date: 1/6/2004 10:26:25 AM
 > Subject: Re: Please help with capacitor
 >
 > Original poster: "Gerry Reynolds" <gerryreynolds-at-earthlink-dot-net>
 >
 > Philip,
 >
 > Resonance for you transformer is about 10.6 nf.  13 nf might be too close
to
 > resonance and your safety gap setting will be important.  You might try 16
 > nf for an LTR value.
 > (assuming 60 Hz)
 >
 > Gerry R
 > Ft Collins. CO
 >
 >  > Original poster: "Philip Brinkman" <peeceebee-at-mindspring-dot-com>
 >  >
 >  > I'm making a new flat plate capacitor for use with my 15,000 volt 60 ma
 >  > NST. I'm using aluminum foil plates 7.5"x9" (67.5 sq. in.) with 30 mil
 >  > polyethelyne (6 layers of 5 mil each) between each plate. Using the
 > formula
 >  > C=kA/d (k=2 ) I get 3.25 sq. meters or 74 plates, does this sound
right?
 > My
 >  > last capacitor had only 30 plates. I'm aiming for .013 microfarads.. is
 >  > this right? Using different programs I get different values of
capacitor
 > to
 >  > use.
 >  >
 >  >
 >