RE: Capacitor - series?

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Luke" <Bluu-at-cox-dot-net> 

Thank you.
That's what I thought all along from applying the electronics school
stuff from way back.  Glad to hear I wasn't off my rocker.

Luke Galyan
Bluu-at-cox-dot-net

-----Original Message-----
From: Tesla list [mailto:tesla-at-pupman-dot-com]
Sent: Sunday, February 08, 2004 8:06 PM
To: tesla-at-pupman-dot-com
Subject: Re: Capacitor - series?

Original poster: Mddeming-at-aol-dot-com

In a message dated 2/8/04 7:24:31 PM Eastern Standard Time,
tesla-at-pupman-dot-com writes:
Original poster: "Luke" <Bluu-at-cox-dot-net>

Ok all this has me a bit confused.
I am STILL of the inclination that:
the two caps WILL NOT see the same voltage
if they are of DIFFERENT VALUES.

Some are saying they will see the same voltage.

What seems to be the verdict among the guys that know their stuff?

Luke Galyan

Hi Luke,
      The answer to your original question is "YES". The voltage drop
across
each cap will be inversly proportional to the capacitance. Smaller
capacitance will have larger voltage drop. Q1=C1V1=C2V2=Q2. In terms of
AC
voltage and current, V1=IXc, V2=1IXc2.  Phil's suggestion of simple
measurement for those who aren't convinced by algebra 1, should settle
the
question once and for all. It is a matter of physical fact, not subject
to
debate or opinion. Take two caps of very different size, wire them in
series with an AC supply and check the voltage across each with a DMM.
It
doesn't have to be thousands of volts to show that the voltage drops are

radically different. "Careful experiment & measurement is the final
arbiter
of all science."

Matt D.