[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: Saskia?s toroidal secondary
Original poster: "Gerry Reynolds" <gerryreynolds-at-earthlink-dot-net>
hi Jared,
It is very kind of you to put this together and offer to send me the
toroidal coil. I am curious in general about coils and resonances and my
interest has been mostly one of learning more about this area. I feel you
and Paul and Antonio are both at the Phd level and lot of the discussion is
beyond my MSEE level. I still find it interesting and I'm able to relate to
enough of the discussion to keep my interest.
I'm not sure I would know what to do with the coil and probably Paul could
make better use of it. I bet in the end the two of you would find more in
common agreement then not. Thankyou for thinking of me.
Regards,
Gerry Reynolds
> Original poster: "Jared E Dwarshuis" <jdwarshui-at-emich.edu>
>
> To Mr. Garry Reynolds:
>
> Hello from Larry Morris and Jared Dwarshuis.
>
> Mr. Reynolds you seem very curious about our toroidal coil, so we will
> explain to you how it works. The inductance for the Saskia?s secondary
> coil is frequency-dependent. With a full wave you calculate the
> inductance as L = u Nsqrd Area / length (where length is one fourth of
> the average of the circumference). With two wavelengths the inductance
> is based on one eighth of the average circumference, with three
> wavelength the length is one twelfth, and so on. You base inductance
> on inter-node distance, it?s really that simple, and of course:
> Frequency = (n/2) x ( C/ wire length)
>
> We have found that Medhurst?s is also inter-nodal and therefore
> frequency-dependent as well, following the exact same trends as above.
> So for a full wave you calculate the Medhurst from one quadrant and
> subtract this from capacitance total before splitting the value between
> the two voltage nodes.
>
> It seems odd that Medhurst?s would not be cumulative, but if you start
> looking at calculations carefully you will see that this must be true
> or the coil would be completely swamped with self capacitance and not
> function properly at any predicted frequency. We do not have an exact
> value for the Medhurst capacitance with this topology, so for now we go
> with the inter-node length and radius and use the cylinder equivalent.
>
> Periodicity implies that each periodic section experiences the same
> changes in potential and current. It should not be a big surprise that
> the inductance and self capacitance are both inter-nodal.
>
> Some features of our L.C. formulae and correspondence: Our wire length
> L.C. formulae are rather simple, it extends the original equations of
> Tesla to the general case and reflects the periodicity of standing
> waves. You will see that these equations are all consistent with
> remarks in the first paragraph above.
>
> (n/2)( C/wire-length) = 1/ 2pi sqrt [ ( u x (N/2n)sqrd x Area x
> (2n/heith) ) Capacitance ]
>
> Examples: a quarter wave represents one half of a node so n = 1/2.
> Plug in this value and the formulae reduces to the old familiar quarter
> wave equation where you solve for capacitance and subtract Medhurst?s
> to find the top end capacitance. (The old familiar!)
>
> A half wave has two half nodes so n = 1. Then C/ twice the wire length
> = 1 / 2pi sqrt [ (1/2 the length of the solenoids L ) x cap]. So in
> a nut shell for a half wave we calculate C/ twice the solenoids total
> wire to find the tank frequency. Then we solve for capacitance total,
> from this you subtract the Medhurst value of 1/2 of the solenoid
> height. Since we have two voltage nodes we split this top end
> capacitance value between both ends (like setting the tension on a rope
> by using a split spring on both ends).
>
>
> With a Marsha configuration you have a split system, so the rules are a
> bit different, but not much. Strictly speaking Marsha?s configuration
> is a full wave, but it represents a full wave as two disjointed half
> waves running anti ?symmetrically. We can describe this system with n =
> 2 for the wire length frequency but you must consider each coil as its
> own L.C. The upshot is that each individual coil from the pair follows
> the same math as the half wave where n = 1. So you are really making
> two half waves that react and have the equivalence of a full wave where
> n = 2. This sounds a bit like a song and dance, but it?s not, it all
> follows directly from the rules. (Think ropes and tension.)
>
> The Levi?s configuration could also be described in a complicated and
> consistent fashion as n = 4 but again it is simpler to calculate it as
> two individual coils where n = 2. And then simply split the top end
> capacitance across the two coils as opposed to within a coil.
>
> It is remarkable how much energy transfers across two part groundless
> resonators through free space capacitive coupled displacement currents.
>
> Our extended correspondence model predicts the behavior of new systems
> so well that we have yet to build a system that hasn?t worked right the
> first time.
>
> The rope derivations written by Jacob and Daniel Bernoulli are
> frighteningly complicated, we got our extended correspondence with
> careful substitutions borrowed from mass spring system correspondence
> and some careful mapping with a relativistic argument. These
> substitutions all hold true logically, but of course we really need a
> complete proof to describe standing wave resonant transformers in the
> Maxwell/Heaviside vector calculus form.
>
> One of the interesting features of our model is that it predicts that
> the lumped form L.C. (with math borrowed from mass spring) will
> manifest itself at precise locations and at specific frequencies within
> an inductor. It would be grand to see this formally resolved.
>
> I don?t want to get into the details of rope resonance, it is something
> that really needs to be played with to be understood in any sort of
> intuitive way. Also the equations of a standing wave require a bit of
> ink to explain. In shorthand, we send an E.M, wave through a uniformly
> distributed medium (the inductor). If the wavelength is correct it
> will form standing waves within the boundaries as the reflected waves
> impose on transmitted waves. The Saskia secondary forms standing waves
> all by itself without reflection, as transmitted waves are induced by
> the primary in both directions (Lenz law), we can make Levi
> configurations, but the price to pay is that we can only form resonance
> with n = 2, 4 ,6, 8,?..
>
> Send us your address and we will send you one of our prototypes. It was
> only made as a proof of concept device, it has tiny wires and a high
> frequency, don?t expect big sparks. I hope that it will be helpful to
> you, it is a horribly addictive toy, and you will want two large ones
> right away. (The inductor cores don?t need a perfect match but make
> sure the wire length exactly the same or the Levi configuration just
> work right).
>
> A fun variation on the Levi configuration is the "Uncle Stumpy" this is
> where you use a single coil with one capacitor and no breakout to drive
> a full wave coil with breakouts, you get sparks across the un-driven
> coil but not between the coils. We have just scratched the surface of
> what is possible, haven?t even looked at the potential for Magnifier
> designs.
>
> You can send our cool toy to Paul in Manchester when you are done, some
> fun would do him good. We are still going to tell his mom that he
> called us names. We would sort of like the coil back by next summer. If
> it gets busted somewhere, or you loan it out to someone who loans it
> out to?, don?t worry about it.
>
> Enjoy your summer, Larry and Jared.
>
>