Re: nobody knows whos maggie at fla teslathon?

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Antonio Carlos M. de Queiroz" <acmq-at-compuland-dot-com.br> 

Tesla list wrote:

 > Original poster: "D&M's High Voltage" <DMsHV.DavMcKin-at-verizon-dot-net>

I have run some numbers:

 > Base coil (Black one in the pictures):  12" diameter wound 32" (48" form)
 > with 12 Ga. heavy build magnet wire for approx. 360 turns.

L2=12.51 mH

 > Magnifier (Tertiary coil on the plywood base):  12" diameter wound 42" (48"
 > form) with 18 Ga. heavy build magnet wire for approx. 930 turns.

L3=65.97 mH

 > Toroid:  20" x 72" chicken wire mesh.

C3=About 105 pF including with the self-capacitance of L3.

 > The primary is an adjustable primary
 > (1/2" tube with approx. 9 turns spaced 1" center of tube to center of tube,
 > inner diameter approx. 15-3/4").  I think it finally tuned in somewhere
 > around 6 turns or so.  We had it very loosely coupled (approx. 6" total),
 > and then started increasing the coupling (by raising the primary approx.
 > 3-1/2").

At 6 turns, 3.5" below the base of L2: L1=27.13 uH, k12=0.127
At 6 turns, 6"   below the base of L2: L1=12.51 uH, k12=0.0914

With C1=133 nF, the system is approximately in tune (C2=0,
C1L1=C3(L2+L3)) with C3=45.98 pF.

Observations:

The toroid appears to be too big for C1=133 nF.
For a true 6th-order magnifier, the coupling coefficient between L1
and L2 is too low, or L2 is too big. The energy stored in the
capacitance
at the connection between L2 and L3 is not transferred to C3, unless
the elements follow the relation k12=sqrt(L2/(L2+L3)). In this case,
the relation gives k12=0.399.

Antonio Carlos M. de Queiroz