[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: NST power rating [non] con
Original poster: davep <davep-at-quik-dot-com>
> > I don't believe this is a verification of the
> > maximum power transfer
> > principle. The tests indicate that the maximum power
> > available from a NST is
> > only about one quarter not one half of the nameplate
> > rating.
Nameplate ratings must fir on the nameplate.
Sometimes, they have nonobvious meanings, which
will be found in the manual/data sheet/ or 'craft
knowledge' for the intended application.
>I was not arguing the point that the transformer
>should deliver its stated short circuit amperage ALSO
>AT its stated voltage rating. To me this sounds
>nonsensible. A 24 inch neon placed across my 15,000
>volt rated NST will only show about 500-600 volts
>across it,
That's the nature of neon lamps.
>and also at less then the short circuit
>current rating.
Current drawn depends on load, among other
things. If the lamp doesn't draw it, that's to
do with the lamp..
>You had stated;
>The maximum secondary watts output was 59.3 watts,
>3900 volts, 15.2 ma.
> >From this comment I had deduced that you tried a
>variety of combinations, and it was this one that gave
>the best results. It was from that standpoint that I
>made the comment that this sounds like the principle
>of maximum power transfer.
>Here is some background info on the principle;
>I will cite from Herbert W Jackson's Introduction to
>Electric Circuits.(3rd edition) I have found his
>descriptions very consise, and here he gives 4
>statements concerning the matter of how internal
>resistance of a stator emf influences the conductions
>on the load.
>1. Maximum power output (into the load) occurs when
>R(L) = R(int)
>Also when R(L) is selected for maximum load power
>I = 1/2 I (short circuit current)
>V(L) = 1/2 E (open circuit voltage)
>This is also 1/2 maximum efficiency
>Note that maximum power output does NOT coincide with
>maximum efficiency. When a load resistance is selected
>for maximum power input, there is an equal power
>dissipation inside the source of emf.
>2. If we want to increase the efficiency, a load
>resistance of from two to three times the internal
>resistance of the generator results in appreciable
>reduction in wasted power ( as heat in the generator)
>for only a small reduction in power output.
>3. A load resistance less than the internal resistance
>of the generator not only results in a reduction of
>power output, but also causes a very high dissipation
>within the generator. In practice, this condition of
>operation is termed OVERLOAD and must be avoided.
>4. If we are interested more in voltage output than
>power output (as in transistor and vacuum-tube
>amplifiers), the load resistance should be high in
>comparsion to the internal resistance of the source
>of emf.
>What I was doing here was to simply compare the NST
>secondary as if it were a generator source of emf.
>This may be a mistaken approach, but it seems apt.
NSTs are designed to include current limiting,
internally.
'power transformers' are designed for max power
out/maximum efficiency.
NST's are designed to match the specific, negative
resistance, characteristic of a gas discharge ('neon')
lamp, and to protect that lamp by not over currenting it.
best
dwp
.