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Re: nobody knows whos maggie at fla teslathon?
Original poster: "colin.heath4" <colin.heath4-at-ntlworld-dot-com>
hi gerry,
on my six inch coil i was running sync for a while and running
at about .85 power factor.
the trick is to use your primary ballast to set up the charging circuit
frequency.
obviously you cant do this with standard static gaps.
at 400bps i would run at approx 90hz charging frequency.
cheers
colin
----- Original Message -----
From: Tesla list <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Wednesday, October 01, 2003 3:15 PM
Subject: Re: nobody knows whos maggie at fla teslathon?
> Original poster: "Gerry Reynolds" <gerryreynolds-at-earthlink-dot-net>
>
> I think the P in the equation is the true power from the line (ie VA *
PF).
> Seems like this result is good. Working backwards, 16 feet would
> correspond to a Power of 12.7 KWatts. With a 18 KVA input that would
imply
> a power factor of .7 I don't yet know what is possible with a SRSG, but
I
> believe the best PF one can get with a static gap is something around 0.5
> without allowing resonant rise to overvolt the transformer (per Richie
> Burnett).
>
> Others please comment. This is an area I want to learn more about.
>
> Gerry R
> Ft Collins, CO
>
> > Original poster: "RMC" <RMC-at-richardcraven.plus-dot-com>
> >
> > > It doesn't take a lot of time to realise the magnifier in question
> isn't
> > > much of a very efficient device.
> > > Power input 18 kVA and observed max arc lenght of 16 feet.
> > > Formula ,frequently mentioned on this list,L(inches)=1.7*SQRT(P)
gives
> 19
> > > footers for that power.
> >
> > That is still 84% of what the empirical formula estimates. Besides, the
> > empirical formula I think has been developed to quantify two-coil TCs,
not
> > magnifiers.
> >
> > I think to say that the device "isn't ...very efficient" is a bit
unfair.
> > How much better have other people achieved...or have you achieved?
> >
> >
> > RMC, England
> >
> >
>
>