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Re: Charge distribution on a Toroid (was spheres vs toroids)
Original poster: "Antonio Carlos M. de Queiroz" <acmq-at-compuland-dot-com.br>
Tesla list wrote:
>
> Original poster: Paul Nicholson <paul-at-abelian.demon.co.uk>
> It's hard to get any work done with windows - ditch it for a proper
> OS! For C compiling, install gcc.
Delphi (Pascal) is good. I am doing now everything with a free Delphi 3.
And it's easy (apparently) to port to Linux using Kylix.
> For a sphere with 200 rings, the value is 31.83135%.
>
> Ah, 1/pi then?
Indeed! I found it by trying. This number looked familiar...
> Wonder how
> you get on with objects that have edges?
I can try an open hemisphere, that has also a simple expression for
capacitance (now using 1/pi of the maximum radius as tube radius):
Hemisphere with 1 meter of diameter:
Exact: 45.5246270366 pF
10 rings: 44.9288700205 pF
20 rings: 45.2259355350 pF
40 rings: 45.3749442201 pF
80 rings: 45.4496825615 pF
200 rings: 45.4946218478 pF
> I suspect that the ideal
> spacing ratio depends on the curvature of the modelled surface
> at that 'latitude', and would therefore vary for each pair of
> adjacent rings: 1/pi +/- some curvature-related term?
Possibly. I will try to prove that 1/pi. Maybe it's the correct
value for a flat surface, producing the same far field.
> > Gauss' law. Really, I don't have to calculate the electric field.
>
> Yup, easy isn't it!
For a closed surface, yes.
> > and the electric field is E=p/(2*e0). [hmm]
I looked again at that book. This division by 2 is exactly at the center
of the charged layer. For breakdown voltage over a closed surface, the
value to use is really E=p/e0.
> If the charge density is p, then the total flux from an infinitesimal
> area dA is p*dA/e0. If this flux were to come out equally on both
> faces of the area then the flux out of each face is p*dA/(2*e0) and
> the flux density on each face is p/(2*e0). But here we have a closed
> surface, so we are entitled to say that all the flux comes off the
> outer surface, thus the surface field strength is actually E=p/e0.
My error was trivial. I was considering the diameter of a sphere as
its radius, what produces 2 V/m/V for a "1 m sphere" (1m of diameter).
> Note that our use of single layer potentials doesn't tell us how the
> flux is shared between the two faces, only the total. For closed
> objects we already know the answer, but for partially open objects,
> eg the tube of the secondary we would have to calculate some E values
> for each side of the surface and apportion the charge pro-rata.
> (Or, model two surfaces for each conductor, and put E=0 inside the
> conductor to complete the system of equations).
The last approach is realistic. I was imagining a kind of "image method"
where I calculate the charges in a set of rings inside the object,
considering the voltages at points of the surface. The electric field
could then be calculated directly at the surface.
> Sorry, I got my units mixed up! It should be 3.53 V/m/V, I forgot
> my program reported in V/cm/V.
I get a maximum of 3.5341105020 V/m/V with 200 rings at the largest
diameter. Breakdown voltage=848.86989 kV
> Yes, tssp gives 1.01436 V/m/V for the 1m sphere in 135 rings. That's
> the highest field that it finds on the surface, so shows, if you like,
> the max positive error. C = 111.185pF (tssp), 111.265pF (4*pi*e0)
I get C=111.2650023882 pF with 200 rings. (Cexact=111.2650056054 pF)
> Something wrong there. Your're ok for the sphere but not the toroid.
Removing the /2 everything seems to work. Reviewing the toroids:
(Rmax/pi radius, 200 rings, Maximum electric field = 3 MV/m)
Size Bela Tssp (C Max field Breakout) Inca (C Breakout)
12 x 3: 302 kV 14.01pF, 9.87 V/m/V, 304kV 13.11 pF 250.6 kV
16 x 4: 386 kV 18.68pF, 7.40 V/m/V, 405kV 17.48 pF 334.2 kV
20 x 5: 458 kV 23.35pF, 5.92 V/m/V, 507kV 21.84 pF 417.7 kV
26 x 6: 532 kV 30.48pF, 4.50 V/m/V, 667kV 28.03 pF 522.0 kV
34 x 8.5: 795 kV 39.69pF, 3.48 V/m/V, 862kV 37.14 pF 710.1 kV
48 x 12: 1353 kV 56.03pF, 2.47 V/m/V, 1215kV 52.43 pF 1003. kV
12 sph: 850 kV 33.89pF 3.33 V/m/V, 901kV 33.91 pF 914.4 kV
> The tssp figures are for the toroid in free space, not in a room.
> I expect the agreement would be better if we put in your room sizes,
> since tssp diverges from Bela when the toroid size increases.
> There's something a bit funny about the 48x12 model.
I will redo the simulation. The toroid capacitances calculated by
Bela seem to be always wrong.
Antonio Carlos M. de Queiroz