Re: SSTC idea

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Yurtle Turtle by way of Terry Fritz <teslalist-at-qwest-dot-net>" <yurtle_t-at-yahoo-dot-com>


--- Tesla list <tesla-at-pupman-dot-com> wrote:
 > Original poster: "Jim Lux by way of Terry Fritz
 > <teslalist-at-qwest-dot-net>" <jimlux-at-earthlink-dot-net>
<snip>
 >
 > Take some example numbers...  100 kHz resonant
 > frequency, 20 kV voltage, 120
 > bps, 1200 Watts.
 > First, what's the joules/bang.. 1200Watts/120
 > bangs/sec = 10 Joule/bang, so
 > now we know that the capacitor is big enough to hold
 > 10 Joules at 20 kV..
 > Using E = 1/2 * C * V^2 >>> 20 = C * 400, for V in
 > kV and C in uF.. C =
 > 20/400 = 0.05 uF.. (50 nF)
 > Now, figure out L to get the fres.. 628E3 =
 > 1E6*sqrt(1/(L*0.05))  (for L&C
 > in uH and uF) 1/(.628^2)/.05 = L >> L=51 uH
 > Now figure out peak primary current (assuming energy
 > in L = energy in C)..
 > 10 = 1/2*L*I^2 >> 20/sqrt(51E-6) = I... 2.8 kA

Boy it's early morning (for me) but I believe that
should be: I=sqrt(10/((.5)(51E-6)))=626.2amps. Or did
I miss something?

Adam

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