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Re: MMC cap bank
Original poster: "Terry Fritz" <teslalist-at-qwest-dot-net>
Hi Jimmy,
At 01:12 PM 7/4/2003 -0700, you wrote:
>Hi Terry,
>
>I understand the I^2R thing, but isn't the RMS current
>only square root of 10 times as much? After you square
>and average it, it would be 10 times, but you still
>have to take the square root, right?
Nope. RMS is just the "equivalent" AC current to a fixed DC current. If I
run 10X the BPS rate, I draw 10X the current and get 100X the heat loss
across a resistor.
>If it really is 500 watts lost with 1000 BPS, then the
>amount of energy lost per pulse is 0.5 joules. If you
>lose 5 watts at 100 BPS, then the energy lost per
>pulse is 0.05 joules. What would cause the increase in
>loss per break?
It's not linear. "I^2" The graph is a steep ski slope.
>We are talking about the same energy
>per pulse right?
Yes. Power = current squared times resistance. Double the current, four
times the power. Triple the current, nine times the power...
>--- Tesla list <tesla-at-pupman-dot-com> wrote:
> > Original poster: "Terry Fritz" <teslalist-at-qwest-dot-net>
> >
> > Hi Jimmy,
> >
> > Suppose we have 10 amps RMS at 100 BPS and our caps
> > are 0.05 ohm of
> > internal resistance (typecal for a 15/60). From
> > P=I^2R the power lost as
> > heat in the caps is 5 watts. Now lets hook it to a
> > pole transformer and
> > run it at 1000 BPS for 100 amps RMS:
>Use my signature Allow HTML tags [Preview]
>
> >
> > P = I^2 x R == 100^2 x 0.05 = 500 watts.
> >
> > The array can run all day at 5 watts. But 500
> > watts it will die
> > fast!! Probably like 15 seconds.
> >
> > Cheers,
> >
> > Terry
> >
> > At 09:07 PM 7/3/2003 -0700, you wrote:
> >
> > > > Second, keep the BPS rate LOW. Capacitor
> > current is
> > > > directionally
> > > > proportional to BPS. 3000 BPS has 10X the
> > current
> > > > of 300 BPS and 100X the
> > > > cap heating!!!
> > >
> > >Hi Terry,
> > >
> > >I "think" the heating should only be 10x as much.
> > If
> > >it were 100x then each burst would have to waste
> > 10x
> > >the power, and I don't see how that is possible.
> > The
> > >average current will be 10x as much, but the RMS
> > will
> > >only be SQRT10x as much because the duty cycle is
> > >greater. Check me on this because it's getting late
> > >for me ;-)).
> > >
> > >=====
> > >Jimmy
> >
> >
>
>
>
>=====
>Jimmy