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Re: Picofarad Capacitor Standard
Original poster: "Jim Lux" <jimlux-at-earthlink-dot-net>
Oh, Ho.... the standard capacitor thing..
Check out NBS Circular 74... it has how to build standard capacitors...
As a practical matter, if you're working at a known frequency, a long
coaxial line might be the best approach, because, especially in the shorted
form, it has a well defined value, with end effects taken care of.
Cragg
----- Original Message -----
From: "Tesla list" <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Tuesday, December 09, 2003 5:13 PM
Subject: Picofarad Capacitor Standard
> Original poster: "John H. Couture" <couturejh-at-mgte-dot-com>
>
>
> Paul N, Antonio, All -
>
> I have attempted to make a homemade capacitor with a reasonably exact
> capacitance value at the low picofarad level for toroid research. This
> capacitor consists of two flat metal plates at a certain distance from one
> another. The main problem of this type of capacitor at low pf capacities
> would be the edge effects. I have tested the capacitor and developed three
> curves as shown below to find where they intersect when varying the
distance
> between the plates. I believe the point of intersection of the curves is
> where the edge effects are eliminated? In other words the plates at .25
> inches giving 40 pf would be the real world capacitance of the two plates
> with the elimination of edge effects.
>
> The theoretical equation for two metal plates at a distance d apart in air
> is
>
> Picofarads = 8.85 (area sq meters)/(d meters)
>
> 1 inch = 39.37 inches
> 1 sq meter = 39.37^2 = 1550 sq inches
>
> Picofards = (39.37/1550) sq inches/inches
> " = .225 sq inches/inches
> 10 pf = .225 sq inches/1
> Area sq inches = 10/.225 = 44.4 (6"x7.42")
>
> pf1 - Theoretical capacity y = 10 X^(-1)
> pf2 - Beckman DM25L y = 21.3 X^(-0.45)
> pf3 - Wavetek DM27XT y = 15.6 X^(-623)
>
> The equations above are power regression equations obtained from Excel.
Note
> that the 3 curves intersect near the d = 0.250 inches point. You can make
a
> graph that illustrates this condition by entering the values into your
Excel
> program and using the Chart Wizard.
>
> d inches pf1 pf2 Pf3
> 0.125 80 56 55
> 0.250 40 40 38
> 0.500 20 28 25
> 0.750 13.3 23 19
> 1.000 10 21 15
> 1.500 6.7 19 12
>
> The values for pf2 and pf3 were adjusted for leads, etc. The two meters
are
> rated +/- 2%+4 for the 2nf range. The results above show that the meters
> only agree with each other and with the theoretical capacitor at the point
> of intersection
> (d = .25"). This is also the point where the capacitor edge effects are
> eliminated?
>
> I would be interested in all comments.
>
> John Couture
>
> ------------------------------------
>
>