RE: Tube regulator for removing ripple . . .

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Mccauley, Daniel H by way of Terry Fritz <teslalist-at-qwest-dot-net>" <daniel.h.mccauley-at-lmco-dot-com>


Are you worried more about ripple or regulation?  I took a quick look at an
ARRL handbook (1990 edition) and they give a guideline of Lcrit =
Eout(Volts)/Iload (mA), so for 4000V and 1A, it would be 4H, a reasonable
size for an iron core choke.

Reference data for Radio Engineers gives a design equation of
ripple/output = 0.83/(LC) where L is in H and C in uF

plugging in your number of 10V ripple (RMS or peak?)
10/4000 = 0.83/(4*C) >>> C = .83/4*4000/10 >>> C = .83*4000/40 = 83 uF

But.. make that a 20 H inductor, instead of 4H, and you're down to 16-17
uF...

20H is certainly reasonable


 >>>>>An LC filter like this does reduce the ripple considerable (less than
30V p-p) for a 20H series inductor and
10uF capacitor, however with that huge inductor your output voltage now
drops from about 3.2kV (capacitive filter only)
down to about 2kV (with the 20H series inductor)

The Captain