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RE: Potting Diode Strings
Original poster: "Loudner, Godfrey by way of Terry Fritz <twftesla-at-qwest-dot-net>" <gloudner-at-SINTE.EDU>
Hello Alex
Not entirely a waste. Suppose you had a bank of big 10 kV pulse capacitors
and a 15 kV neon sign transformer. The rectifier below can be use to charge
the bank at 7.5 kV. The peak voltage would be (7500 volts) x (square root of
2) = 10,607 volts. Now one would be business for high current discharge
experiments. I know of someone who is using this arrangement to make the big
discharge bangs.
Godfrey Loudner
> -----Original Message-----
> From: Tesla list [SMTP:tesla-at-pupman-dot-com]
> Sent: Tuesday, March 26, 2002 8:52 AM
> To: tesla-at-pupman-dot-com
> Subject: Re: Potting Diode Strings
>
> Original poster: "Alexander Rice by way of Terry Fritz
> <twftesla-at-qwest-dot-net>" <alex-at-rices.myip-dot-org>
>
> 26/03/2002 00:32:55, "Tesla list"
> <tesla-at-pupman-dot-com> wrote:
> Hi Malcom,
> >Original poster: "Malcolm Watts by way of
> Terry Fritz <twftesla-at-qwest-dot-net>"
> <m.j.watts-at-massey.ac.nz>
> >>
> >> AC_1---------->|---|
> >> |
> >> |
> >> CT-------LOAD------|
> >> |
> >> |
> >> AC_2---------->|---|
> >
> >The main problem with that configuration is
> that you aren't making
> >best use of the copper in the windings. Only
> one half of the
> >secondary is delivering power at any one
> time. A bridge would be the
> >way to go in my book. You still only need
> the same number of diodes
> >and they would be distributed in four
> strings rather than two.
> >
> >Regards,
> >Malcolm
>
> I know, i realised this soon after i sent it,
> rectifying it like this means you only get
> about half the peak ac voltage - which sucks
> for TC applications.
>
> Regards
>
> Alex
>
>
>