Re: Bleeder resistor

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Jim Lux by way of Terry Fritz <twftesla-at-qwest-dot-net>" <jimlux-at-earthlink-dot-net>

P = E^2/R... 20E3*20E3/50E6 = 400/50 = 8W

As a practical matter, you'll probably be more limited by HV breakdown over
the resistor.  A 2W carbon resistor is probably good for 2 kV, breakdown
wise.  So a string of 10 resistors: 5 Meg at 2W, would be a likely candidate...

For what it's worth, none of this stuff is critical.. It's always a
tradeoff between power dissipation in the bleeder and "time til safe"....
Say you make it a string of 10Meg resistors instead (100Meg total)... Now
the dissipation is only 4 W, and you've doubled the time to 1 minute..

By the way, a minute (or even 30 seconds) is a VERY long time to wait when
you want to work on something.  You could probably afford to burn up 20-30
Watts in the bleeders (not on a small NST coil, though, where this would be
10% of the power!) and cut the "time to 50V" down to 10 seconds or so..

Tesla list wrote:
> 
> Original poster: "by way of Terry Fritz <twftesla-at-qwest-dot-net>"
<Dan_Gallagher%PULSARNOTES-at-pulsartech-dot-com>
> 
> Hi Jim, Terry and all,
> 
> Jim, thanks for the info on bleeders. You say 50megohms for a .01uf cap.
> What wattage resistor would this be?
> 
> Thanks
> 
> getting closer..............
> Dan
> Ft. Lauderdale