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Re: Is toroid a Faraday cage?
Original poster: "davep by way of Terry Fritz <twftesla-at-qwest-dot-net>" <davep-at-quik-dot-com>
> There has to be charge on the interior.
Faraday, and like measurements since him, disagree.
(Hint:
One can charge the outside with a slightly modified
van de Graaf. Or an e beam. Put an electrometer
inside and observe (eg optically...)
> If all electric charge resided on the exterior, there would
> be a nett voltage across the thickness of the metal which
> would be accompanied by a heavy current flow.
Charge is different than voltage ...
Picture the electrons as a mutually repulsive
gas. Add some (leaving the original neutral set
intact). The added, unbalanced ones will mutually
repel to the outside of a faraday cage.
Note, however that a toroid is not a cage, in the
usual sense. Since the surface of the DONUT is
conductively connected, charge anywhere on the
surface of the donut will equalize. The INSIDE
space (the inner volume of the tube, the inner
surface of the donut, NOT the 'hole')) (hard to
describe without pictures.)
best
dwp
...the net of a million lies...
Vernor Vinge
There are Many Web Sites which Say Many Things.
-me