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Re: Is toroid a Faraday cage?



Original poster: "davep by way of Terry Fritz <twftesla-at-qwest-dot-net>" <davep-at-quik-dot-com>

> There has to be charge on the interior.


	Faraday, and like measurements since him, disagree.

	(Hint:
	One can charge the outside with a slightly modified
	van de Graaf.  Or an e beam.  Put an electrometer
	inside and observe (eg optically...)

> If all electric charge resided on the exterior, there would

> be a nett voltage across the thickness of the metal which

> would be accompanied by a heavy current flow.


	Charge is different than voltage ...

	Picture the electrons as a mutually repulsive
	gas.  Add some (leaving the original neutral set
	intact).  The added, unbalanced ones will mutually
	repel to the outside of a faraday cage.

	Note, however that a toroid is not a cage, in the
	usual sense.  Since the surface of the DONUT is
	conductively connected, charge anywhere on the
	surface of the donut will equalize.  The INSIDE
	space (the inner volume of the tube, the inner
	surface of the donut, NOT the 'hole')) (hard to
	describe without pictures.)

	best
	dwp

...the net of a million lies...
	Vernor Vinge
There are Many Web Sites which Say Many Things.
	-me