RE: MOT current draw question

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Loudner, Godfrey by way of Terry Fritz <twftesla-at-qwest-dot-net>" <gloudner-at-SINTE.EDU>

Hi Terry

Wouldn't it be 4,000 volts/10,000 ohms = 0.4 amps. giving two times the
power, not four. By coil I assume you mean the HV winding of the mot.  

Godfrey Loudner

> -----Original Message-----
> From:	Tesla list [SMTP:tesla-at-pupman-dot-com]
> Sent:	Friday, January 18, 2002 7:48 PM
> To:	tesla-at-pupman-dot-com
> Subject:	Re: MOT current draw question
> 
> Original poster: "Terry Fritz" <twftesla-at-qwest-dot-net>
> 
> Hi,
> 
> At 09:48 AM 1/19/2002 +0900, you wrote:
> .......
> >JW replied:
> >
> >Hey, I'm also having the same problem....I was doing a 2 MOT series...and
> it 
> >looked like I was pulling 120V -at- 20A out of a 15A plug! I got a 13" arc
> at 4 
> >kV....then "BANG!" I overloaded the 15A breaker. My peak output would be
> 4kV 
> >-at- 600 mA!!
> >...my smallr MOT's are only sucking 6.6A on 120V.....but they can draw 3
> X 
> >that amount in series!
> >
> 
> I guess this is not surprising.  Consider if the MOTs put out 2000 volts
> each and you coil is 5000 ohms.  With one MOT you have 2000 volts at 0.4
> amps.
> 
> Two MOTs give 4000 volts at 0.8 amps.  But the power in the first case is
> 800 watts and in the second case it is 3200 watts.  For the 120VAC to
> supply 800 watts takes 6.66 amps but you need 26.66 amps (4X) in the
> second
> case.  
> 
> So if you double the secondary voltage, you get 4 times the power and need
> four times the input current.
> 
> Hope that is sort of clear as to what I mean...
> 
> Cheers,
> 
> 	Terry
>