Re: capacitor calculations

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Terry Fritz" <twftesla-at-qwest-dot-net>

Hi Jesse,

The voltage will still be 6000 volts.  The voltage is the sum of the caps
in series.  Two caps in series gives 4000V, five gives 10000 volts, etc.
Putting caps in parallel does not change the voltage it just adds to the
capacitance.

Cheers,

	Terry


At 10:40 PM 1/8/2002 -0800, you wrote:
>Ok, that much makes sense. now what if I use those
>three in series then add another identical series
>string in paralel 6 caps total.  capacitence should
>equal 100nf  but at what voltage?  (i hope that was
>clear enough)
>
>Thanks 
>Jesse
>--- Tesla list <tesla-at-pupman-dot-com> wrote:
>> Original poster: "Terry Fritz" <twftesla-at-qwest-dot-net>
>> 
>> Hi Jesse,
>> 
>> The voltages add.  So if you put three 150nF 2000V
>> caps in series you get
>> 1/3 the capacitance and three times the voltage or
>> 50nF 6000V.  See the
>> chart at:
>> 
>> http://hot-streamer-dot-com/temp/MMCcapSales.gif
>> 
>> Cheers,
>> 
>> 	Terry
>> 
>> At 04:40 PM 1/8/2002 -0800, you wrote:
>> >Hello, Quick question
>> >I am at a point where I need to start thinking
>> about
>> >building a capacitor.  I have decided to go with
>> the
>> >MMC.  Now I understand the adding and dividing of
>> >capacitance depending on how they are wired
>> together,
>> >but how do the voltages work to get the desired
>> high
>> >voltage value?  Does voltage also change depending
>> on
>> >wiring characteristics or is it something else?
>> >
>> >Thank You 
>> >
>> >Jesse Hampton 
>> >