Re: secondary voltage

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Terry Fritz" <twftesla-at-qwest-dot-net>

Hi Tom,

That equation comes from conservation of energy.  However, it does not take
into account gap losses and such which may account for up to 50% of a coils
energy loss.  A good modification is:

Vout = 0.7 x Vin x SQRT(Cpri / Csec)

Note the square root function too.

So with the numbers you give, I get 313kV which is probably fairly close.

Cheers,

	Terry


At 05:23 PM 6/17/2001 +0200, you wrote:
>Hi coilers
>I've heard of a formula to calculate the secondary voltage.It is 
>U(out)=U(in)*C(prim)/C(sec).
>My primary C is 40 nF,my secondary (coil+toroid) 20 pF,so this is a 
>relationship of 2000:1.The effective input voltage is 7300 V,so the peak 
>voltage is abt 10 kV.That would mean I have a  sec. voltage of 
>20.000.000 V.And anyhow I can't believe this.Someone wants to clear 
>things up for me ?
>
>Tom
>