Re: Average, RMS and Power Factor made easy!

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Ed Phillips by way of Terry Fritz <twftesla-at-uswest-dot-net>" <evp-at-pacbell-dot-net>

Tesla list wrote:
> 
> Original poster: "35045 by way of Terry Fritz <twftesla-at-uswest-dot-net>"
<free0076-at-flinders.edu.au>
> 
> On Sat, 20 Jan 2001, Tesla list wrote:
> 
> >
> >       For a square wave the average equals the peak equals the RMS.
> >
> > Ed
> >
> 
> That's just plain wrong! If the average equals the peak you MUST have DC.
> In that case the average=peak=RMS... You are thinking of DC not the square
> wave we are discussing.
> 
> Have fun,
> Darren Freeman

	Correct!  Delete the reference to "average" and I stand by the rest. 
Next time I'll try to remember not to post something while my wife is
trying to talk to me!

Ed