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MOT w/doubler question
Original poster: "Peter Lawrence by way of Terry Fritz <twftesla-at-uswest-dot-net>" <Peter.Lawrence-at-Eng.Sun-dot-com>
I'm trying to make sure I understand how a voltage doubler (like in a
microwave oven circuit) works
+------------+-------------------- HV out
| |
--- |
CAP |
--- |
| |
| -
| D
x S w I
f e i O
r c n D
m d d E
r r i -
y n |
| g |
| |
+------------+--------------------
|
|
GND
If I am understanding this correctly, the top of the xfrmer secondary winding
does +1900v to -1900v and back at 60 Hz; 120 peaks counting both + and - (???).
The "HV out" does 0 while the diode is conducting, and (2 * 1900), ie the
sum of the secondary V plus the CAP V, while the diode is non-conducting,
at 60 Hz; 60 peaks, pulsing DC ie only one polarity (???).
Therefore: TC using MOT w/ voltage doubler will do 60 BPS. (?)
(or maybe more if the Tank cap can be charged multiple times in one (half)
cycle).
The way I see it (someone correct me if I'm wrong) putting two MOTs w/doublers
in series with common ground you get (4*1900v) at 60 BPS and it is pulsating
DC, at least if you connect everything up correctly (swap one of the diodes
from the way it was in the M-O, and connect the primaries in anti-parallel)...
+------------+-------------------- HV out
| |
--- |
CAP |
--- |
| -
| V diode
S -
E |
C |
| |
+------------+-------------------- GND
| |
C |
E |
S -
| V diode
| -
--- |
CAP |
--- |
| |
+------------+-------------------- HV out
thanks,
Pete Lawrence.