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*To*: tesla-at-pupman-dot-com*Subject*: Re: Cap voltage - time*From*: "Tesla list" <tesla-at-pupman-dot-com>*Date*: Thu, 22 Feb 2001 08:01:18 -0700*Resent-Date*: Thu, 22 Feb 2001 08:52:55 -0700*Resent-From*: tesla-at-pupman-dot-com*Resent-Message-ID*: <XCOroB.A.ebG.1WTl6-at-poodle>*Resent-Sender*: tesla-request-at-pupman-dot-com

Original poster: "Antonio Carlos M. de Queiroz by way of Terry Fritz <twftesla-at-uswest-dot-net>" <acmq-at-compuland-dot-com.br> Tesla list wrote: > > Original poster: "Jim Lux by way of Terry Fritz <twftesla-at-uswest-dot-net>" <jimlux-at-earthlink-dot-net> > > When charged from a constant current source, V = I * T/C > When charged from a constant voltage source through a resistor > V = Vcharge * (1-exp(-T/(R*C)) > where exp(x) is e^x, where e = 2.71828459045.... > Units: Ohms, Volts, Farads(!), Seconds For general calculations, the first formula is very useful. It is the simplest case of the general case for linear capacitors: V(t0+T)=V(t0)+1/C*Integral from t0 to t0+T of I(t) If you know the average value of the current I in the time interval T: Variation in V = (T/C)*Average of I. (e=2.7182818284...) Antonio Carlos M. de Queiroz

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