Re: Coupling Coefficient

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Paul Nicholson by way of Terry Fritz <twftesla-at-qwest-dot-net>" <paul-at-abelian.demon.co.uk>

Matt,

> http://home.earthlink-dot-net/~electronxlc/difmodel/coupling.html
 
That's a wickedly complicated explanation!  I don't see what you
gain by introducing four mystery quantities - Kp, Ks, Np, and Ns.
Why not exploit the fact that physically there is only one - the
coupling coefficient K?

To your translated circuit model, assign:

  Lm = M
  L1 = Lp - M
  L2 = Ls - M

where M is as usual K * sqrt(Lp * Ls), and proceed from there.

Then you only need the single measurement of part 1, since

 E2 = (M/Lp) * E1 
    = K * sqrt( Ls/Lp) * E1

Regards,
--
Paul Nicholson,
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