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*To*: tesla-at-pupman-dot-com*Subject*: Re: for Inductance Calculation*From*: "Tesla list" <tesla-at-pupman-dot-com>*Date*: Sat, 14 Apr 2001 21:39:57 -0600*In-Reply-To*: <36.146830a4.280a68e7-at-aol-dot-com>*Resent-Date*: Sat, 14 Apr 2001 22:07:43 -0600*Resent-From*: tesla-at-pupman-dot-com*Resent-Message-ID*: <4r9K1.A.jRG.M6R26-at-poodle>*Resent-Sender*: tesla-request-at-pupman-dot-com

Original poster: "Terry Fritz" <twftesla-at-uswest-dot-net> Hi Matt, Inductors (coils) resist current "sort of" like resistors do. "Reactance" is used much like resistance to figure out such things. Xl = 2 x pi f x L Where: Xl = Reactance of the inductor pi = 3.14159... f = the frequency of the circuit L = the coil's inductance You can use Xl just like you use resistance for many things. If you have a 10 Henry inductor and the LC circuit oscillates at say 10kHz (Fo = 1/(2 x pi x SQRT(L x C)) Then Xl = 2 x pi x 10000 x 10 == 628000 This number can be used much like resistance so that if you have 450 volts the current is: I = 450 / 628000 == 0.716 amps That is really over simplified but gives you the idea of how it is done. The equation are at: http://home.earthlink-dot-net/~electronxlc/formulas.html You may want to ask a few more specific questions since this is kind of a "fast course" in this very messy subject... There are also a few details like damping in an energy limited (capacitor discharge) circuit that may be important... Cheers, Terry At 11:00 PM 4/14/2001 -0400, you wrote: >How do you figure out peak amperage in a circuit?Like I have a 7000uF 450 >volt cap(this is off topic but is related)and is discharged into a flat >spiral coil of 12 turns and its diam is about 2 milli. > >Matt >

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