Re: for Inductance Calculation

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Terry Fritz" <twftesla-at-uswest-dot-net>

Hi Matt,

Inductors (coils) resist current "sort of" like resistors do.  "Reactance"
is used much like resistance to figure out such things.

Xl = 2 x pi f x L

Where:

Xl = Reactance of the inductor
pi = 3.14159...
f = the frequency of the circuit
L = the coil's inductance

You can use Xl just like you use resistance for many things.

If you have a 10 Henry inductor and the LC circuit oscillates at say 10kHz
(Fo = 1/(2 x pi x SQRT(L x C))

Then Xl = 2 x pi x 10000 x 10 == 628000

This number can be used much like resistance so that if you have 450 volts
the current is:

I = 450 / 628000 == 0.716 amps

That is really over simplified but gives you the idea of how it is done.
The equation are at:

http://home.earthlink-dot-net/~electronxlc/formulas.html

You may want to ask a few more specific questions since this is kind of a
"fast course" in this very messy subject...  There are also a few details
like damping in an energy limited (capacitor discharge) circuit that may be
important...

Cheers,

	Terry


At 11:00 PM 4/14/2001 -0400, you wrote:
>How do you figure out peak amperage in a circuit?Like I have a 7000uF 450 
>volt cap(this is off topic but is related)and is discharged into a flat 
>spiral coil of 12 turns and its diam is about 2 milli.
>
>Matt
>